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Arlecino [84]
3 years ago
13

A restaurant needs to plan seating for a party of 150 people. Large tables seat 10 people and small tables seat 6. Let x represe

nt the number of large tables and y represent the number of small tables. Write an equation in standard form to represent this situation.
Mathematics
1 answer:
grandymaker [24]3 years ago
4 0

Answer:

(0, 25) or (3, 20) or (6, 15) or (9, 10) or (15, 0)

Step-by-step explanation:

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Time sensitive question. Find the sum of the first 26 terms of an arithmetic series whose first term is 7 and 26th term is 93.
lisabon 2012 [21]

ANSWER

S_{26}=1300

EXPLANATION

The sum of an arithmetic sequence whose first term and last terms are known is calculated using

S_{n}= \frac{n}{2} (a + l)

From the given information, the first term of the series is

a = 7

and the last term of the series is

l = 93

The sum of the first 26 terms is

S_{26}= \frac{26}{2} (7 + 93)

S_{26}= 13 (100)

S_{26}=1300

7 0
3 years ago
Five pairs of socks are in a drawer. Three pairs
Hitman42 [59]

Answer: 40% chance

Sample space: 3 white 2 red, 5 pairs

2/5 probability, as a percent would be 40% chance

3 0
3 years ago
Elaluate the expression when y=5 and x=47. x - 6y ​
lys-0071 [83]

Answer:

1410

Step-by-step explanation:

-6 times 5 is -30

47 times -30 is -1410

6 0
3 years ago
Read 2 more answers
What are some useful ways of finding equivalent fractions and equivalent ratios
Ratling [72]
What ever you do to one number you have to do to the other
6 0
3 years ago
What fraction of the students in the class named baseball their favorite sport
mojhsa [17]

now, let's take a peek at the denominators, we have 3 and 8 and 12, we can get an LCD of 24 from that.

Let's multiply both sides by the LCD of 24, to do away with the denominators.

so, let's recall that a whole is "1", namely 500/500 = 1 = whole, or 5/5 = 1 = whole or 24/24 = 1 = whole.  So the whole class will yield a fraction of 1/1 or just 1.

\bf ~\hspace{7em}\stackrel{\textit{basketball}}{\cfrac{1}{3}}+\stackrel{\textit{soccer}}{\cfrac{1}{8}}+\stackrel{\textit{football}}{\cfrac{5}{12}}+\stackrel{\textit{baseball}}{x}~=~\stackrel{\textit{whole}}{1} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \stackrel{\textit{multiplying both sides by }\stackrel{LCD}{24}}{24\left(\cfrac{1}{3}+\cfrac{1}{8}+\cfrac{5}{12}+x \right)=24(1)}\implies (8)1+(3)1+(2)5+(24)x=24 \\\\\\ 8+3+10+24x=24\implies 21+24x=24\implies 24x=3 \\\\\\ x=\cfrac{3}{24}\implies x=\cfrac{1}{8}

4 0
3 years ago
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