ANSWER

EXPLANATION
The sum of an arithmetic sequence whose first term and last terms are known is calculated using

From the given information, the first term of the series is

and the last term of the series is

The sum of the first 26 terms is



Answer: 40% chance
Sample space: 3 white 2 red, 5 pairs
2/5 probability, as a percent would be 40% chance
Answer:
1410
Step-by-step explanation:
-6 times 5 is -30
47 times -30 is -1410
What ever you do to one number you have to do to the other
now, let's take a peek at the denominators, we have 3 and 8 and 12, we can get an LCD of 24 from that.
Let's multiply both sides by the LCD of 24, to do away with the denominators.
so, let's recall that a whole is "1", namely 500/500 = 1 = whole, or 5/5 = 1 = whole or 24/24 = 1 = whole. So the whole class will yield a fraction of 1/1 or just 1.
![\bf ~\hspace{7em}\stackrel{\textit{basketball}}{\cfrac{1}{3}}+\stackrel{\textit{soccer}}{\cfrac{1}{8}}+\stackrel{\textit{football}}{\cfrac{5}{12}}+\stackrel{\textit{baseball}}{x}~=~\stackrel{\textit{whole}}{1} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \stackrel{\textit{multiplying both sides by }\stackrel{LCD}{24}}{24\left(\cfrac{1}{3}+\cfrac{1}{8}+\cfrac{5}{12}+x \right)=24(1)}\implies (8)1+(3)1+(2)5+(24)x=24 \\\\\\ 8+3+10+24x=24\implies 21+24x=24\implies 24x=3 \\\\\\ x=\cfrac{3}{24}\implies x=\cfrac{1}{8}](https://tex.z-dn.net/?f=%5Cbf%20~%5Chspace%7B7em%7D%5Cstackrel%7B%5Ctextit%7Bbasketball%7D%7D%7B%5Ccfrac%7B1%7D%7B3%7D%7D%2B%5Cstackrel%7B%5Ctextit%7Bsoccer%7D%7D%7B%5Ccfrac%7B1%7D%7B8%7D%7D%2B%5Cstackrel%7B%5Ctextit%7Bfootball%7D%7D%7B%5Ccfrac%7B5%7D%7B12%7D%7D%2B%5Cstackrel%7B%5Ctextit%7Bbaseball%7D%7D%7Bx%7D~%3D~%5Cstackrel%7B%5Ctextit%7Bwhole%7D%7D%7B1%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20%5Crule%7B34em%7D%7B0.25pt%7D%5C%5C%5C%5C%20%5Cstackrel%7B%5Ctextit%7Bmultiplying%20both%20sides%20by%20%7D%5Cstackrel%7BLCD%7D%7B24%7D%7D%7B24%5Cleft%28%5Ccfrac%7B1%7D%7B3%7D%2B%5Ccfrac%7B1%7D%7B8%7D%2B%5Ccfrac%7B5%7D%7B12%7D%2Bx%20%5Cright%29%3D24%281%29%7D%5Cimplies%20%288%291%2B%283%291%2B%282%295%2B%2824%29x%3D24%20%5C%5C%5C%5C%5C%5C%208%2B3%2B10%2B24x%3D24%5Cimplies%2021%2B24x%3D24%5Cimplies%2024x%3D3%20%5C%5C%5C%5C%5C%5C%20x%3D%5Ccfrac%7B3%7D%7B24%7D%5Cimplies%20x%3D%5Ccfrac%7B1%7D%7B8%7D)