We need to divide 4,971 by 10 until its a number less then 10.
4,971 / 10 = 497.1
497.1 / 10 = 49.71
49.71 / 10 = 4.971
Now, 4.971 is less then 10, so, we can write this into scientific notation.
4.971 * 10^?
We need to know what power we add to 10 to get 4,971. We can solve for looking at the number of times we divided. As you can see above, we divided 3 times so that will be the power of 10.
4.971 * 10³
Best of Luck!
I see that you are in high school, and I'm hoping that you've been introduced
to differential calculus, because I don't know how to answer this question without
using it.
We're told that Jason's height above the water is <em>H(t) = -16t² + 16t + 480 .</em>
We can observe many things from this equation:
-- Up is the positive direction; down is the negative direction.
-- The acceleration of gravity is 32 ft/sec² .
-- Jason jumps upward from the cliff, at 16 ft/sec .
-- The cliff is 480-ft above the water.
(This tells us why the question is only concerned with his maximum height,
and then it ends ... 480-ft is one serious cliff, and what happens after the
peak of his arc is too gruesome to contemplate.)
In any case, his vertical velocity is the first derivative, with respect to time,
of his height above the water.
V = -32 t + 16
At the peak of his arc, where gravity takes over, his velocity changes from
upward to downward, and it's momentarily zero.
0 = -32t + 16
Add 32t to each side: 32t = 16
Divide each side by 32: <em> t = 1/2 second</em>
His height at that instant is H(0.5) = -16(0.5)² + 16(0.5) + 480 =
<em>4-ft above the cliff, 484-ft above the water</em>,
and then he begins falling from that altitude.
The duration of his dive is 484 = 16 t²
t = √(484/16) = <em>5.5 seconds</em>
and he hits the water at V = a t = (32) x (5.5) = 176 ft/sec = <em>exactly 120 mph </em>
Jason was good man ... a good student, and always kind to everyone he met.
He will certainly be missed.
The greater number is 21, this is correct since 21 + 3 is 24, and 21 - 3 is 18. Thus, it fulfills all necessary requirements
Answer:
Given:
n = 15
c = 95% = 0.95
Let us assume:
α = 0.05
Determine the difference in value of each pair.
→See attached for the table←
→See attached for the for the workings←
Result
a) There is sufficient evidence to reject the claim that the two methods provide the same mean value for natural vibration frequency.
b) (-10.9646, -0.0068)
