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3 years ago

For what values of n will the sum n+3 be less than 50

Mathematics

1 answer:

Goryan [66]3 years ago

6 0

N+3<50
n<47 is your solutions

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HELP ASAP GIVING BRAINLIEST

Alborosie

Hey sorry if I’m wrong but I think it is the 665 sorry if I’m wrong let me know

8 0

3 years ago

Read 2 more answers

WILL GIVE BRAINLIEST!!!

s2008m [1.1K]

1. Can you describe what needs to be done here?

2. 5a-2<18

5a<20

a<4

3. 2a+8≥ -4(a+1)

2a + 8 ≥ -4a - 4

6a ≥ -12

a ≥ -2

8 0

3 years ago

What is the distance from the point (3,8) to the point (7,-6)?

oksano4ka [1.4K]

Answer: Distance is 14.6

Step-by-step explanation:

$d = √((x2-x1)2 + (y2-y1)2)$

$(x2-x1) = (7 - 3) = 4$

$(y2-y1) = (-6 - 8) = -14$

add it all together

$(4)2 + (-14)2 = 16 + 196 = 212$

Square 212

$\sqrt{212} =14.5602$

round to the nearest tenth

=14.6

PLEASE MARK BRAINLIEST

5 0

3 years ago

Read 2 more answers

A roast turkey is taken from an oven when its temperature has reached 185 degrees F and is placed on a table in a room where the

Vedmedyk [2.9K]

(a) Using Newton's Law of Cooling, $\dfrac{dT}{dt} = k(T - T_s)$ , we have $\dfrac{dT}{dt} = k(T - 75)$ where T is temperature after T minutes.
Separate by dividing both sides by T - 75 to get $\dfrac{dT}{T - 75} = k dt$ . Integrate both sides to get $\ln|T - 75| = kt + C$ .

Since $T(0) = 185$ , we solve for C:
$|185 - 75| = k(0) + C\ \Rightarrow\ C = \ln 110$
So we get $\ln|T - 75| = kt + \ln 110$ . Use T(30) = 150 to solve for k:
$\ln| 150 - 75 | = 30k + \ln 110\ \Rightarrow\ \ln 75 - \ln 110= 30k \Rightarrow \\ k= \frac{1}{30}\ln (75/110) = \frac{1}{30}\ln(15/22)$

So

$\ln|T - 75| = kt + \ln 110 \Rightarrow |T - 75| = e^{kt + \ln110} \Rightarrow \\ \\
|T - 75| = 110e^{kt} \Rightarrow T - 75 = \pm110e^{(1/30)\ln(15/22)t} \Rightarrow \\
T = 75 \pm110e^{(1/30)\ln(15/22)t}$

But choose Positive because T > 75. Temp of turkey can't go under.

$T(t) = 75 + 110e^{(1/30)\ln(15/22)t} \\
T(45) = 75 + 110e^{(1/30)\ln(15/22)(45)} = 136.929 \approx 137{}^{\circ}F$

(b)

$T(t) = 75 + 110e^{(1/30)\ln(15/22)t} = 75 + 110(15/22)^{t/30} \\
100 = 75 + 110(15/22)^{t/30} \\
25 = 110(15/22)^{t/30} 
\frac{25}{110} = (15/22)^{t/30} \\
\ln(25/110) / ln(15/22) = t/30 \\
t = 30\ln(25/110) / ln(15/22) \approx 116\ \mathrm{min}$

Dogs of the AMS.

4 0

3 years ago

Find the perimeter of the figure to the nearest hundredth. Ps: it is not 30

frutty [35]

Answer:

Perimeter = 36.8 ft

Step-by-step explanation:

Step 1: Add the straight sides together

3+3+3+3+3+3 = 18 ft

Step 2: Find the perimeter of the semi-circles

The formula for the perimeter of semi-circle: 1/2 π × d

Diameter = 12 - 3 - 3 = 6, because the whole length is 12 minus the 6 ft of other stuff.

Now, 1/2π * 6 = 9.4 ft

But, there are two semi-circles so it will be 9.4 + 9.4 = 18.8 ft

Step 3: Add all of them

18 + 18.8 = 36.8 ft

8 0

3 years ago