Question

Find the four terms of the sequence given by the following expression

Answer 1

Answer:

47, 40, 33, 26 are the first four terms of the sequence.

Step-by-step explanation:

Expression representing the sequence is,

$a_n=46-7(n-1)$

where n = number of term in the sequence

For n = 1,

$a_1=47-7(1-1)$

    = 47

For n = 2,

$a_2=47-7(2-1)$

    = 47 - 7

    = 40

For n = 3,

$a_3$ = 47 - 7(3 -1)

   = 47 - 14

   = 33

For n = 4,

$a_4=47-7(4-1)$

    = 47 - 21

    = 26

Therefore, first four terms of the sequence are 47, 40, 33 and 26.