If we assume the given segments are those from the vertices to the point of intersection of the diagonals, it seems one diagonal (SW) is 20 yards long and the other (TR) is 44 yards long. The area (A) of the kite is half the product of the diagonals:
... A = (1/2)·SW·TR = (1/2)·(20 yd)·(44 yd)
... A = 440 yd²
Scientific notation:
8.41 x 10^7
expanded form:
84100000
Answer:
a) 0.6435 radians
b) 80.1 feet/sec
Step-by-step explanation:
a) 75 = (50²/16)sin(theta)cos(theta)
sin(theta)cos(theta) = 0.48
2sin(theta)cos(theta) = 0.96
sin(2theta) = 0.96
2theta = 1.287002218
Theta = 0.6435011088 radians
b) 200 = (v²/16)sin(0.75)cos(0.75)
6416.072347 = v²
v = 80.10038918 feet/sec
The answer is B
hope this helps
Answer:
Step-by-step explanation:
