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3 years ago

Write two word sentences for the equation of r/0.2=40.

Mathematics

1 answer:

VikaD [51]3 years ago

6 0

Answer:

1) The quotient of r and 0.2 is equal to 40.

2) r divided by 0.2 is equal to 40.

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-18+-6 please help

Verdich [7]

Answer:

-24

Step-by-step explanation:

If you are struggling with this here's a tip!

-18+-6 is what you are trying to solve

The 6 is negative, so get rid of the plus sign -18-6

2 negative numbers are just added like positive numbers

So add 18 and 6, you should get 24

Don't forget about the negative!

-24

6 0

2 years ago

A baseball team lost 4 more games than it won. If the team played 46 games, how many did it lose? How many did it win?

blsea [12.9K]

The team won 27 games and lost 19

4 0

2 years ago

6c – 7 + d + 4 – 6d combine like terms

kkurt [141]

Answer:

6c-5d-3

Step-by-step explanation:

6c-7+d+4-6d=6c-5d-3

5 0

2 years ago

1. Express <img src="https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7Bx%282x%2B3%29%20%7D" id="TexFormula1" title="\frac{1}{x(2x+3) }" a

katovenus [111]

1. Let a and b be coefficients such that

$\dfrac1{x(2x+3)} = \dfrac ax + \dfrac b{2x+3}$

Combining the fractions on the right gives

$\dfrac1{x(2x+3)} = \dfrac{a(2x+3) + bx}{x(2x+3)}$

$\implies 1 = (2a+b)x + 3a$

$\implies \begin{cases}3a=1 \\ 2a+b=0\end{cases} \implies a=\dfrac13, b = -\dfrac23$

so that

$\dfrac1{x(2x+3)} = \boxed{\dfrac13 \left(\dfrac1x - \dfrac2{2x+3}\right)}$

2. a. The given ODE is separable as

$x(2x+3) \dfrac{dy}dx} = y \implies \dfrac{dy}y = \dfrac{dx}{x(2x+3)}$

Using the result of part (1), integrating both sides gives

$\ln|y| = \dfrac13 \left(\ln|x| - \ln|2x+3|\right) + C$

Given that y = 1 when x = 1, we find

$\ln|1| = \dfrac13 \left(\ln|1| - \ln|5|\right) + C \implies C = \dfrac13\ln(5)$

so the particular solution to the ODE is

$\ln|y| = \dfrac13 \left(\ln|x| - \ln|2x+3|\right) + \dfrac13\ln(5)$

We can solve this explicitly for y :

$\ln|y| = \dfrac13 \left(\ln|x| - \ln|2x+3| + \ln(5)\right)$

$\ln|y| = \dfrac13 \ln\left|\dfrac{5x}{2x+3}\right|$

$\ln|y| = \ln\left|\sqrt[3]{\dfrac{5x}{2x+3}}\right|$

$\boxed{y = \sqrt[3]{\dfrac{5x}{2x+3}}}$

2. b. When x = 9, we get

$y = \sqrt[3]{\dfrac{45}{21}} = \sqrt[3]{\dfrac{15}7} \approx \boxed{1.29}$

8 0

2 years ago

Two students have partially simplified the same expression. Audrey's work: ( x3y−2 22x−5y3 ) 3 = ( x8y−5 22 ) 3 = x24y−15 26 Dav

Crank

Answer:

<h3>-<u>Aubrey first applied division of like bases by subtracting the exponents.</u></h3><h3>-<u>Next David will apply the quotient of powers.</u></h3><h3><u>-Aubrey's work is correct .</u></h3><h3><u>-The correct simplified answer is x^24/64y^15</u></h3>

4 0

2 years ago

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