Leanna is making a craft and needs 12 yards of ribbon. If 2 yards of ribbon cost $1.25, how much will 12 yards cost?
1 answer:
You might be interested in
Answer:
<h2>7/8 gallons of Ginger ale </h2>Step-by-step explanation:
Total gallons of punch mixture = gallons of pineapple juice + orange juice + gallons of apple juice + gallons of Ginger ale
Given gallons of pineapple juice = 3/4 gallons
Orange juice = 1 1/2 gallons
Gallons of apple juice = 7/8
Total gallons of punch = 4 gallons
On substituting into the formula above:
4 =
]
gallons of ginger ale =
gallons ginger ale =
She needs 7/8 gallons of Ginger ale to make the total of 4 gallons of punch
The correct question in the attached figure
we know that
applying the law of sines
g/sinG=k/sinK
g=3 units
G=30°
k=4 units
K=?
so
g/sinG=k/sinK------> g*sinK=k*sinG-----> sinK=k*sinG/g
sinK=4*sin 30°/3-----> 2/3
K=arc sin(2/3)-------> K=41.81°
case 1)
for angle K=41.81°
the sum of the angles (H +G+K)=180°
H=180-(G+K)------> 180-(30+41.81)--------> H=108.19°
h/sinH=g/sinG-------> h=g*sinH/sinG------> h=3*sin 108.19°/sin 30°
h=5.70 units
case 2)
for angle K=180°-41.81°---------> K=138.19°
the sum of the angles (H +G+K)=180°
H=180-(G+K)------> 180-(30+138.19)--------> H=11.81°
h/sinH=g/sinG-------> h=g*sinH/sinG------> h=3*sin 11.81°/sin 30°
h=1.2 units
therefore
the answer is the option
<span>A. 1.2 or 5.7</span>
we know that
applying the law of sines
g/sinG=k/sinK
g=3 units
G=30°
k=4 units
K=?
so
g/sinG=k/sinK------> g*sinK=k*sinG-----> sinK=k*sinG/g
sinK=4*sin 30°/3-----> 2/3
K=arc sin(2/3)-------> K=41.81°
case 1)
for angle K=41.81°
the sum of the angles (H +G+K)=180°
H=180-(G+K)------> 180-(30+41.81)--------> H=108.19°
h/sinH=g/sinG-------> h=g*sinH/sinG------> h=3*sin 108.19°/sin 30°
h=5.70 units
case 2)
for angle K=180°-41.81°---------> K=138.19°
the sum of the angles (H +G+K)=180°
H=180-(G+K)------> 180-(30+138.19)--------> H=11.81°
h/sinH=g/sinG-------> h=g*sinH/sinG------> h=3*sin 11.81°/sin 30°
h=1.2 units
therefore
the answer is the option
<span>A. 1.2 or 5.7</span>