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3 years ago

To Find the IQR in a Box Plot, you take Q1-Q3?

Mathematics

2 answers:

ankoles [38]3 years ago

6 0

Answer:

True

Step-by-step explanation:

You subtract Q3 from Q1 and that is how you find the IQR

Ray Of Light [21]3 years ago

4 0

False to find IQR in a box plot you do Q3-Q1

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What is the answer to this math question!?

Nostrana [21]

Answer:

C) 37

Step-by-step explanation:

1/2(PQ)=RQ

2.5x+17=6x-11

17=3.5x-11

28=3.5x

x=8

RQ=6(8)-11

RQ=48-11

RQ=37

5 0

2 years ago

Read 2 more answers

jocelyn bought 2 sweaters for the same price. she paid 23.56,including sales tax of 1.36 and a 5.00 discount coupon. what was th

wel

Number of sweaters bought by Jocelyn = 2
Price of the 2 sweaters including tax and discount coupon = 23.56
Amount of ales tax taken = 1.36
Amount of discount coupon = 5.00
Then
Price of 2 sweaters before tax = 23.56 - 1.36
   = 22.20
Then
Price of the sweater before discount coupon was applied = 22.20 + 5.00
   = 27.20
So
Price of 1 sweater before tax and coupon discount = 27.2/2
   = 13.6
So the price of 1 sweater before tax and coupon discount is 13.6.

6 0

3 years ago

Find the missing measures for the rectangle

Vadim26 [7]

Do you have a picture or something to accompany the question?

5 0

2 years ago

The oven tray is 600mm by 500mm. A cake tin is 25cm in diameter. How many cake tins can jenny fit on the oven tray at one time?

vlada-n [284]

Area of Circle= $\pi 
$ $r^{2}$
= $\frac{22}{7}$ x $( \frac{25cm}{2}) ^{2}$
= 490.87 $cm^{2}$

Area of Oven tray= 60cm x 50cm
= 3000 $cm^{2}$

: . # tin that can hold on bake tray= 3000 $cm^{2}$ / <span>490.87 $cm^{2}$ = 6.11
Thus making it logically 6..... </span>

8 0

3 years ago

A fisherman uses a spring scale to weigh a tilapia fish. He records the fish weight as a kilograms and notices that the spring s

belka [17]

Answer:

k = $\frac{980a}{b}$

Step-by-step explanation:

Fisherman noticed a stretch in the spring = 'b' centimetres

Weight of the fish = a kilograms

If force applied on a spring scale makes a stretch in the spring then Hook's law for the force applied is,

F = kΔx

Where k = spring constant

Δx = stretch in the spring

F = weight applied

F = mg

Here 'm' = mass of the fish

g = gravitational constant

F = a(9.8)

= 9.8a

Δx = b centimetres = 0.01b meters

Therefore, 9.8a = k(0.01b)

k = $\frac{9.8a}{0.01b}$

k = $\frac{980a}{b}$

Therefore, spring constant of the spring will be determined by the expression, k = $\frac{980a}{b}$

4 0

2 years ago