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3 years ago

What is the volume of a square that's sides are 5cm, 3cm, 8cm, 12cm?

Mathematics

1 answer:

Tpy6a [65]3 years ago

6 0

Answer:

what is the l,w,h? You would do the l,w,h. If it is 5,3,8 do 5*3=15*8=120

Step-by-step explanation:

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If you have a spinner with 5 slots, what is the compound probability of spinning an even number, then an odd number? Expressed a

Minchanka [31]

Since the spinner has 5 slots it contains 3 odd and 2 evens,

Odds ⇒ 1, 3, 5

Evens⇒ 2,4

this can be expressed as

$\frac{2}{5} =\frac{x}{100}$ , cross multiply and we get

$5x=200$

$x=40$ %

6 0

2 years ago

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Add 620 grams to 3.7 kilograms.give your answer in kilogram

Alla [95]

3.7kg is also equal to 3700 grams
3700+620 grams
= 4320 grams
= 4320/1000 kg
= 4.32 kg

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3 years ago

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There are 100 people in a sport centre.

sleet_krkn [62]

By definition of complement,

Pr[not P | G and T] = 1 - Pr[P | G and T]

and by definition of conditional probability,

Pr[not P | G and T] = 1 - Pr[P and G and T] / Pr[G and T]

Pr[not P | G and T] = 1 - (16/100) / (33/100)

Pr[not P | G and T] = 1 - 16/33

Pr[not P | G and T] = 17/33

4 0

3 years ago

What is 57,910,000 in scientific notation

Alexandra [31]

Are there options to this?

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3 years ago

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Suppose a production facility purchases a particular component part in large lots from a supplier. The production manager wants

musickatia [10]

Answer:

We need a sample size of at least 1161.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

The margin of error for the interval is:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

For this problem, we have that:

$\pi = 0.22$

90% confidence level

So $\alpha = 0.1$ , z is the value of Z that has a pvalue of $1 - \frac{0.1}{2} = 0.95$ , so $Z = 1.645$ .

How large a sample should she take?

We need a sample size of at least n.

n is found when $M = 0.02$

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.02 = 1.645\sqrt{\frac{0.22*0.78}{n}}$

$0.02\sqrt{n} = 1.645\sqrt{0.22*0.78}$

$\sqrt{n} = \frac{1.645\sqrt{0.22*0.78}}{0.02}$

$(\sqrt{n})^{2} = (\frac{1.645\sqrt{0.22*0.78}}{0.02})^{2}$

$n = 1160.88$

Rounding up

We need a sample size of at least 1161.

7 0

3 years ago