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2 years ago

I need help please

Mathematics

1 answer:

Triss [41]2 years ago

8 0

She paid $3.28 per gallon.

24.60 divided by 7.5 equals 3.28.

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F(x)=5-2x PLEASE HELP DUE TODAY!!!

EastWind [94]

If f(1) =5-2(1)
F(2)=5-2(2)

3 0

3 years ago

Sam and Bruno were computing how many kilometers they rode in the 3 bike trips they took last month. In order, they rode 45.7, 4

Eddi Din [679]

Answer:

We are given number of miles the 3 bike trips they took last month = 45.7, 40.9, and 38 miles.

Sam and Bruno were computing how many kilometers.

Also one kilometer equals 0.621 miles.

From this we can see than 1 kilometer is smaller unit and a mile is a larger unit.

In order to convert number of miles into kilometers, we need to divide each number of mile by 0.621 miles.

We always divide a larger value by a smaller value to get the smaller unit.

Therefore,

Bruno is correct. When going from a larger unit to a smaller unit you need to divide.

Step-by-step explanation:

Hopefully this helped, if not HMU and I will get u a better answer.

-Have a great day! :)

4 0

3 years ago

Please help me. I need help.

vagabundo [1.1K]

Answer:

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

Solve each compound inequality 10m > 84

Mazyrski [523]

$▪▪▪▪▪▪▪▪▪▪▪▪▪ {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪$

let's solve :

$10m > 84$

$m > \dfrac{84}{10}$

$m > 8.4$

6 0

2 years ago

Math scores on the SAT exam are normally distributed with a mean of 514 and a standard deviation of 118. If a recent test-taker

LuckyWell [14K]

Answer:

Probability that the student scored between 455 and 573 on the exam is 0.38292.

Step-by-step explanation:

We are given that Math scores on the SAT exam are normally distributed with a mean of 514 and a standard deviation of 118.

Let X = Math scores on the SAT exam

So, X ~ Normal( $\mu=514,\sigma^{2} =118^{2}$ )

The z score probability distribution for normal distribution is given by;

Z = $\frac{X-\mu}{\sigma}$ ~ N(0,1)

where, $\mu$ = population mean score = 514

$\sigma$ = standard deviation = 118

Now, the probability that the student scored between 455 and 573 on the exam is given by = P(455 < X < 573)

P(455 < X < 573) = P(X < 573) - P(X $\leq$ 455)

P(X < 573) = P( $\frac{X-\mu}{\sigma}$ < $\frac{573-514}{118}$ ) = P(Z < 0.50) = 0.69146

P(X $\leq$ 2.9) = P( $\frac{X-\mu}{\sigma}$ $\leq$ $\frac{455-514}{118}$ ) = P(Z $\leq$ -0.50) = 1 - P(Z < 0.50)

= 1 - 0.69146 = 0.30854

The above probability is calculated by looking at the value of x = 0.50 in the z table which has an area of 0.69146.

Therefore, P(455 < X < 573) = 0.69146 - 0.30854 = 0.38292

Hence, probability that the student scored between 455 and 573 on the exam is 0.38292.

7 0

3 years ago

I need help please ​

I need help please