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3 years ago

5

write a real world situation that can be represented by 15 + c = 17.50. Then solve the equation and describe what your answer re

presents for the problem situation

2 answers:

VladimirAG [237]3 years ago

7 0

Answer:

The given expression is

$15+c=17.50$

We can use this expression to model the cost for a service.

Let's say that your gardener charges an initial amount of $15, and an additional per hour. If the gardener worked only for one hour, and the total cost charged was $17.50, how much was the additional cost?

So, the given expression models this real life situation, we can answer the problem by just solving the equation for $c$

$15+c=17.50\\c=17.50-15\\c=2.50$

Nana76 [90]3 years ago

3 0

15+c=17.50 First you subtract 15 by 15 because you switch operations from adding to subtracting then you would put C under it Second subtract 17.50 and 15 and that is 2.50 so C= 2.50

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One number is 2 more than another. The difference between their squares is 20. What are the numbers?

ss7ja [257]

Answer:

let x=one number =

x-2= another number

x²- (x-2)²=20

x²-x²-4x+4=20

-4x=20-4

-4x=16

x=16/-4

x=-4

one number is -4

x-2

-4-2

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the another number is -6

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3 years ago

The difference between two numbers is 10 and their sum is 20. Find the biggest number.

marysya [2.9K]

Answer:

15

Step-by-step explanation:

x - y = 10, then x = 10 + y

x + y = 20

substitute for x:

10 + y + y = 20

2y = 10

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3 years ago

9 gal 1 qt+ 6 gal 1 qt = what

wlad13 [49]

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7 0

4 years ago

Read 2 more answers

Solve these linear equations in the form y=yn+yp with yn=y(0)e^at.

WINSTONCH [101]

Answer:

a) $y(t) = y_{0}e^{4t} + 2$ . It does not have a steady state

b) $y(t) = y_{0}e^{-4t} + 2$ . It has a steady state.

Step-by-step explanation:

a) $y' -4y = -8$

The first step is finding $y_{n}(t)$ . So:

$y' - 4y = 0$

We have to find the eigenvalues of this differential equation, which are the roots of this equation:

$r - 4 = 0$

$r = 4$

So:

$y_{n}(t) = y_{0}e^{4t}$

Since this differential equation has a positive eigenvalue, it does not have a steady state.

Now as for the particular solution.

Since the differential equation is equaled to a constant, the particular solution is going to have the following format:

$y_{p}(t) = C$

So

$(y_{p})' -4(y_{p}) = -8$

$(C)' - 4C = -8$

C is a constant, so (C)' = 0.

$-4C = -8$

$4C = 8$

$C = 2$

The solution in the form is

$y(t) = y_{n}(t) + y_{p}(t)$

$y(t) = y_{0}e^{4t} + 2$

b) $y' +4y = 8$

The first step is finding $y_{n}(t)$ . So:

$y' + 4y = 0$

We have to find the eigenvalues of this differential equation, which are the roots of this equation:

$r + 4 =$

$r = -4$

So:

$y_{n}(t) = y_{0}e^{-4t}$

Since this differential equation does not have a positive eigenvalue, it has a steady state.

Now as for the particular solution.

Since the differential equation is equaled to a constant, the particular solution is going to have the following format:

$y_{p}(t) = C$

So

$(y_{p})' +4(y_{p}) = 8$

$(C)' + 4C = 8$

C is a constant, so (C)' = 0.

$4C = 8$

$C = 2$

The solution in the form is

$y(t) = y_{n}(t) + y_{p}(t)$

$y(t) = y_{0}e^{-4t} + 2$

6 0

3 years ago

1) Who in your class has the most pets?

Bess [88]

Answer:

How many siblings does the average 6th-grade student have?

Step-by-step explanation:

In order to know the average, you need to collect all the amounts of siblings 6th grade students have and then you need to add them all together and divide by how much numbers there are and you'll get your average.

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3 years ago