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Effectus [21]
3 years ago
13

Which shows all the prime factors for 36?   A.2 • 18  B.4 • 9  C.2 • 2 • 3 • 3  D.2 • 2 • 3 • 5

Mathematics
1 answer:
DENIUS [597]3 years ago
7 0
36 = 2 x 2 x 3 x 3 (Answer C)
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Order of operations 20/5*2
Xelga [282]
The order of operations is Parenthesis Exponents Multiplication Division Addition Subtraction For this problem, we have M and D. We first do division. Not always multiplication is first. So we divide 20 by 5, which gets you 4, and multiply by 2, which is 8. 8 IS YOUR FINAL ANSWER,
6 0
3 years ago
Read 2 more answers
Suppose that a company needs 1, 200,000 items during a year and that preparation for each production run costs $500. Suppose als
MAVERICK [17]

Answer:

The number of items in each production run so that the total costs of production and storage are minimized is 8165 items/run

Step-by-step explanation:

We will use the following variables:

Q = Quantity being ordered

Q* = the optimal order Quantity: the result being sought

D = annual Demand for the item, over the year

P = unit Production cost

S = cost of setting up a production run, regardless of the number of units in the production run (fixed cost per production run)

H = annual cost to Hold one unit

It is important to note which variables are annualized, which are per-order and which are per-unit.

Using the variables, here are the components of the first equation

Total Cost, TC = PC + SC + HC

PC = P x D :  Production Cost = unit Production cost times the annual Demand

SC = (D x S)/Q : Setting up Cost = annual Demand times cost per production setup, divided by the order Quantity (number of units)

HC = (H x Q)/2: Holding Cost = annual unit Holding cost times order Quantity (number of units), divided by 2 (because throughout the year, on average the warehouse is half full).

So TC = PC + SC + HC =  (P x D) + ((D x S)/Q) + ((H x Q)/2) = PD + (DS/Q) + HQ/2

To obtain the optimal order quantity, Q* that minimizes TC, at the minimum TC, dTC/dQ = 0

dTC/dQ = (H/2) – (D x S)/(Q²) = 0

(H/2) – (D x S)/(Q²) = 0

Solving for Q, which is Q* at this point.

(Q*)² = 2DS/H

Q* = √(2DS/H)

D = annual demand for the item = 200000

S = cost of setting up a production run, regardless of the number of units in the production run (fixed cost per production run) = $500

H = annual cost to Hold one unit = $3

Q* = √(2×200000×500/3) = 8164.97 = 8165 items.

3 0
3 years ago
Question:<br><br>|x-2|, if x &gt; 5<br> simplify without the absolute value sign
nikitadnepr [17]

Answer:

x - 2, if x > 5

Step-by-step explanation:

The vertical lines either side of the expression mean absolute value.

The absolute value of a number is its <u>positive numerical value</u>.

if x > 5 then as 5 > 2, the values inside the vertical lines will always be positive.  Therefore, we can disregard the absolute value.

Therefore:  

x - 2,  if x > 5

To find the range (output values) of the expression, substitute x = 5 into the expression:

⇒ 5 - 2 = 3

Therefore, |x - 2| > 3,  if x > 5

5 0
2 years ago
Find the volume of this triangular prism. Be sure to include the correct unit in your answer.
Alecsey [184]

Answer:

360

Step-by-step explanation:

you just use Rectangular volume length*width*highet then divide 2

you can got it.

6 0
3 years ago
Pls help figure out part c, part e, and part f
Sedbober [7]
Part c : consecutive interior angle
part e: alternate interior angle
part f : vertical angle
7 0
2 years ago
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