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kramer
3 years ago
7

A new restaurant with 131 seats is being planned. Studies show that 62​% of the customers demand a​ "no children" area. How many

seats should be in the​ "no children" area in order to be very sure ​(mu plus 3 sigma​) of having enough seating​ there?
Mathematics
1 answer:
ELEN [110]3 years ago
6 0

Answer:

82

Step-by-step explanation:

According to the study, 62% customer's demand "no children" area, 0.62*131 = 81.22 seats to be very sure there must be 82 seats in "no children" area.

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40% of 125 is what number?
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Solution for 40 is what percent of 125:

40:125*100 =

( 40*100):125 =

4000:125 = 32

Now we have: 40 is what percent of 125 = 32

Question: 40 is what percent of 125?

Percentage solution with steps:

Step 1: We make the assumption that 125 is 100% since it is our output value.

Step 2: We next represent the value we seek with $x$x​.

Step 3: From step 1, it follows that $100\%=125$100%=125​.

Step 4: In the same vein, $x\%=40$x%=40​.

Step 5: This gives us a pair of simple equations:

$100\%=125(1)$100%=125(1)​.

$x\%=40(2)$x%=40(2)​.

Step 6: By simply dividing equation 1 by equation 2 and taking note of the fact that both the LHS
(left hand side) of both equations have the same unit (%); we have

$\frac{100\%}{x\%}=\frac{125}{40}$
100%
x%​=
125
40​​

Step 7: Taking the inverse (or reciprocal) of both sides yields

$\frac{x\%}{100\%}=\frac{40}{125}$
x%
100%​=
40
125​​

$\Rightarrow x=32\%$⇒x=32%​

Therefore, $40$40​ is $32\%$32%​ of $125$125​.
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