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3 years ago

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The regular price of a child's entry ticket to a water park is $6 less than that for an adult's. The park offers half off all en

try tickets during the off-peak season. The Sandlers paid a total of $78 for 1 adult ticket and 2 child's tickets to the water park during the off-peak season. The following equation represents this situation, where x represents the regular price of an adult ticket:
78 = one-halfx + (x − 6)

What is the regular price of a child's ticket?

$50
$56
$75
$81

1 answer:

Anestetic [448]3 years ago

7 0

The price is just 50 dollars

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(PLESE HELP) Factor the following expression. Simplify your answer.

mars1129 [50]

The factor of the expression $5p(p + 2)^{\frac{2}{3} } + 4(p + 2)^{\frac{1}{3} }$ is $(p + 2)^{\frac{2}{3} } (5p^{3} + 10p^{2} + 20p + 4)$

To answer the question, we need to know what factorization is

<h3>What is factorization?</h3>

Factorization is the process of breaking down an expressing into a simpler form containing its factors.

Since

$5p(p + 2)^{\frac{2}{3} } + 4(p + 2)^{\frac{1}{3} }$

Since $(p + 2)^{\frac{1}{3} }$ is common, we factor it out. So, we have

$(p + 2)^{\frac{2}{3} } (5p(p + 2)^{2} + 4)$

Expanding the bracket, we have

$(p + 2)^{\frac{2}{3} } (5p(p^{2} + 2p + 4) + 4) = (p + 2)^{\frac{2}{3} } (5p^{3} + 10p^{2} + 20p + 4)$

So, the factor of the expression $5p(p + 2)^{\frac{2}{3} } + 4(p + 2)^{\frac{1}{3} }$ is $(p + 2)^{\frac{2}{3} } (5p^{3} + 10p^{2} + 20p + 4)$

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1 year ago

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2 years ago

Find the Fourier series of f on the given interval. f(x) = 1, ?7 < x < 0 1 + x, 0 ? x < 7

Zolol [24]

$f(x)=\begin{cases}1&\text{for }-7$

The Fourier series expansion of $f(x)$ is given by

$\dfrac{a_0}2+\displaystyle\sum_{n\ge1}a_n\cos\frac{n\pi x}7+\sum_{n\ge1}b_n\sin\frac{n\pi x}7$

where we have

$a_0=\displaystyle\frac17\int_{-7}^7f(x)\,\mathrm dx$
$a_0=\displaystyle\frac17\left(\int_{-7}^0\mathrm dx+\int_0^7(1+x)\,\mathrm dx\right)$
$a_0=\dfrac{7+\frac{63}2}7=\dfrac{11}2$

The coefficients of the cosine series are

$a_n=\displaystyle\frac17\int_{-7}^7f(x)\cos\dfrac{n\pi x}7\,\mathrm dx$
$a_n=\displaystyle\frac17\left(\int_{-7}^0\cos\frac{n\pi x}7\,\mathrm dx+\int_0^7(1+x)\cos\frac{n\pi x}7\,\mathrm dx\right)$
$a_n=\dfrac{9\sin n\pi}{n\pi}+\dfrac{7\cos n\pi-7}{n^2\pi^2}$
$a_n=\dfrac{7(-1)^n-7}{n^2\pi^2}$

When $n$ is even, the numerator vanishes, so we consider odd $n$ , i.e. $n=2k-1$ for $k\in\mathbb N$ , leaving us with

$a_n=a_{2k-1}=\dfrac{7(-1)-7}{(2k-1)^2\pi^2}=-\dfrac{14}{(2k-1)^2\pi^2}$

Meanwhile, the coefficients of the sine series are given by

$b_n=\displaystyle\frac17\int_{-7}^7f(x)\sin\dfrac{n\pi x}7\,\mathrm dx$
$b_n=\displaystyle\frac17\left(\int_{-7}^0\sin\dfrac{n\pi x}7\,\mathrm dx+\int_0^7(1+x)\sin\dfrac{n\pi x}7\,\mathrm dx\right)$
$b_n=-\dfrac{7\cos n\pi}{n\pi}+\dfrac{7\sin n\pi}{n^2\pi^2}$
$b_n=\dfrac{7(-1)^{n+1}}{n\pi}$

So the Fourier series expansion for $f(x)$ is

$f(x)\sim\dfrac{11}4-\dfrac{14}{\pi^2}\displaystyle\sum_{n\ge1}\frac1{(2n-1)^2}\cos\frac{(2n-1)\pi x}7+\frac7\pi\sum_{n\ge1}\frac{(-1)^{n+1}}n\sin\frac{n\pi x}7$

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2 years ago

The bill for Dino's lunch was $19.45. He wanted to leave 20% of the total bill as a tip. How much should the tip be?

Salsk061 [2.6K]

You could multiply 19.45 by 0.2 to solve for it, but if you're not using a calculator, then 19.45/5 would be much more convenient and easier.

0.2 is 1/5 in fraction form, which is why we can do that.

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Dino should leave $3.89 as a tip.

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3 years ago

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zavuch27 [327]

let the speed of plane in still air be x and that wind be y

therefore:

x+y=490

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x=880/2

x=440 miles per hour.

substituting the value of x in one of the equations and solving for y we get:

440+y=490

y=490-440

y=50 miles per hour

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3 years ago