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3 years ago

Can someone help me with this please

Mathematics

1 answer:

skad [1K]3 years ago

4 0

Answer:

the answer is: 6z^3

Step-by-step explanation:

We need to solve this equation:

$\sqrt{36z^6}$

We know that 6X6 = 36

and √ = 1/2

Solving:

$=\sqrt{6*6*z*z*z*z*z*z}\\We\,\,know\,\,6X6=6^2\,\, and \,\,z*z=z^2\\=\sqrt{6^2*z^2*z^2*z^2} \\=(6^2)^{1/2}*(z^2)^{1/2}*(z^2)^{1/2}*(z^2)^{1/2}\\=6*z*z*z\\=6z^3$

So, the answer is: 6z^3

You might be interested in

If Joanne can paint a room in 3 hours and her sister Angela can paint the same room in 4 hours, how long (in h) would it take Jo

Gala2k [10]

Answer:

Step-by-step explanation:

If J can paint a room in 3 hours, in 1 hour she gets $\frac{1}{3}$ of the job done.

If A can paint a room in 4 hours, in 1 hour she gets $\frac{1}{4}$ of the job done. We need to find out how long it takes them if they paint together. The equation for this is:

$\frac{1}{3}+\frac{1}{4}=\frac{1}{x}$ where x is the number of hours it takes them to get the job done together. Multiply everything through by 12x to get

4x + 3x = 12 so

7x = 12 and

x = 1.7 hours to get the room painted together.

7 0

3 years ago

f a rectangle has a perimeter of 70, a length of x and a width of x - 9, find the value of the length of the rectangle.

trasher [3.6K]

$( x + (x - 9)) \times 2 = 70 \\( 2x - 9) \times2= 70 \\ 4x - 18 = 70 \\ 4x = 70 + 18 = 88$
$x = \frac{88}{4} = 22$
the length is 22

and the width is
22-9=17

good luck

3 0

3 years ago

The time for this event for boys in secondary school is known to possess a normal distribution with a mean of 460 seconds and a

AlekseyPX

Answer:

The time that the boys need to beat in order to earn a certificate of recognition from the fitness association is 511.264 seconds.

Step-by-step explanation:

We are given that the time for this event for boys in secondary school is known to possess a normal distribution with a mean of 460 seconds and a standard deviation of 40 seconds.

The fitness association wants to recognize the fastest 10% of the boys with certificates of recognition.

Let X = time for this event for boys in secondary school

SO, X ~ Normal( $\mu=460,\sigma^{2} =40^{2}$ )

The z-score probability distribution for normal distribution is given by;

Z = $\frac{X-\mu}{\sigma}$ ~ N(0,1)

where, $\mu$ = mean time = 460 seconds

$\sigma$ = standard deviation = 40 seconds

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

Now, it is given that the fitness association wants to recognize the fastest 10% of the boys with certificates of recognition, which means;

P(X > x) = 0.10 {where x is the required time which boy need to beat}

P( $\frac{X-\mu}{\sigma}$ > $\frac{x-460}{40}$ ) = 0.10