Which word in the sentence below is an interrogative pronoun?

A bowl has the shape of a hemisphere whose diameter is 14 centimeters. If this bowl is filled with water, how many cubic centime

ASHA 777 [7]

Answer:

The cubic centimeters of water it will take to fill the bowl is 718.67 cm³

Step-by-step explanation:

Given;

diameter of the hemisphere, d = 14 cm

radius of the hemisphere, r = d/2 = 14/2 = 7 cm

The volume of the hemisphere is calculated as;

$V = \frac{2}{3} \pi r^3\\\\V = \frac{2}{3} \times \frac{22}{7} \times (7 \ cm)^3\\\\V = 718.67 \ cm^3$

The cubic centimeters of water it will take to fill the bowl is 718.67 cm³

4 0

3 years ago

1) -5g-6 for g=-2

jeyben [28]

Answer:

1) A

2) A

3) B

4) D

5)A

6) D

7) A

8) C

9) D

Step-by-step explanation:

1) -5 (-2) -6= 4

2) 3 coins plus c coins = 3 + c

3) x-2 =16, x = 18

4) $\frac{z}{-12}$ =-5. Clearing, z = 60

5) x =13,4

6) 14=t-4. Clearing t = 58

7) -30=j+50, clearing j=80

8) 2.8x=-9.24, clearing x=-3-3

9) 5.8= $\frac{z}{2.2}$ . Clearing z=12.76

4 0

3 years ago

A 128gb Iphone 12 cost $999.00 is 6.25%. How much is the cost of the Iphone inlcuding the sales tax?

anyanavicka [17]

Answer:

1,061.44

Step-by-step explanation:

100%+6.25%=106.25%

convert this to decimal and you get 1.0625

then you just multiply with the initial price

999.00*1.0625=1,061.44

6 0

3 years ago

Read 2 more answers

What is 3 1/2 X 2 X 9 1/3

enot [183]

Answer: 21

Steps: Convert the mixed number to an improper fraction and Reduce the numbers with the greatest common factor

- 7/2 * 2 * 3

Reduce the numbers with the greatest common factor

7 * 3

Answer = 21

7 0

2 years ago

Solve the following equations by factorisation method.Only factorisation not dharacharya.

Luba_88 [7]

Hello, please consider the following.

When $x_1$ and $x_2$ are two roots, we can factorise as

$ax^2+bx+c=a(x-x_1)(x-x_2)=a(x^2-(x_1+x_2)x+x_1x_2)=0$

So for the first equation, we can say that the sum of the zeros is

$\dfrac{a^2+b^2}{2}=\dfrac{a^2}{2}+\dfrac{b^2}{2}$

and the product is

$\dfrac{a^2b^2}{4}=\dfrac{a^2}{2}\dfrac{b^2}{2}$

So we can factorise as below.

$4x^2-2(a^2+b^2)x+a^2b^2=(2x-a^2)(2x-b^2)=0$

And the solutions are

$\boxed{\sf \n\bf \ \dfrac{a^2}{2} \ \ and \ \ \dfrac{b^2}{2}}$

For the second equation, we will complete the square and put the constant on the right side and take the root.

Let's do it!

$9x^2-9(a+b)x+2a^2+5ab+2b^2=0\\\\9(x-\dfrac{a+b}{2})^2-9\dfrac{(a+b)^2}{4}+2a^2+5ab+2b^2=0\\\\9(x-\dfrac{a+b}{2})^2=\dfrac{9(a+b)^2-8a^2-20ab-8b^2}{4}\\\\9(x-\dfrac{a+b}{2})^2=\dfrac{9a^2+18ab+9b^2-8a^2-20ab-8b^2}{4}\\\\9(x-\dfrac{a+b}{2})^2=\dfrac{a^2+b^2-2ab}{4}=\dfrac{(a-b)^2}{4}\\\\(x-\dfrac{a+b}{2})^2=\dfrac{(a-b)^2}{2^2\cdot 3^2}$

We take the root, and we find the two solutions

$\begin{aligned}x_1&=\dfrac{a+b}{2}-\dfrac{a-b}{6}\\\\&=\dfrac{3a+3b-a+b}{6}\\\\&=\dfrac{2a+4b}{6}\\\\&\boxed{=\dfrac{a+2b}{3}}\end{aligned}$

$\begin{aligned}x_1&=\dfrac{a+b}{2}+\dfrac{a-b}{6}\\\\&=\dfrac{3a+3b+a-b}{6}\\\\&=\dfrac{4a+2b}{6}\\\\&\boxed{=\dfrac{2a+b}{3}}\end{aligned}$

Thank you.

6 0

3 years ago