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Andrei [34K]
3 years ago
12

ASAP 10 POINTS IF YOU ANSWER

Mathematics
2 answers:
kiruha [24]3 years ago
5 0

Step-by-step explanation:

-18.4,-17.3,-1.4,7.8,15.8,16.2

Nana76 [90]3 years ago
4 0

Answer:

-18.4 < -17.3 < -1.4 < 7.8 < 15.8 < 16.2

Step-by-step explanation:

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Geometry question help please !!​
seraphim [82]

Answer:

Think simple.

We already have parallelogram LENS, therefore:

∠L ≅ ∠ENS

We also have parallelogram NGTH, therefore:

∠T ≅ ∠GNH

Finally, we can also see that:

∠ENS ≅ ∠GNH (opposite angles)

=> ∠L ≅ ∠T

8 0
3 years ago
What is the product 2•(-7) A.-9<br> B.-2<br> C.-14<br> D.14
Leno4ka [110]

Answer:

-14 (C)

Step-by-step explanation:

2 x -7 would be -14 because 2 x 7 is 14, but since 7 is negative it would be -14/C

6 0
3 years ago
I got most of them but I need help on those 3
Vadim26 [7]
Using Pythagoras:-

x^2  = 6^2 + (sqrt18)^2
       = 36 + 18 = 54

x = sqrt54  =  3 sqrt6
3 0
3 years ago
Which shows how to find the value of this expression when x=-2 and y=5 (3x^3y^-2)^2??
lidiya [134]

Answer:

(3×-2^3×5^-2)^2

Step-by-step explanation:

I think this is it I'm not sure sorry if it's not I tried my best to help you.

7 0
4 years ago
Suppose we are interested in bidding on a piece of land and we know one other bidder is interested.1 The seller announced that t
Usimov [2.4K]

Answer:

0.4

Step-by-step explanation:

Given:-

- The uniform distribution parameters are as follows:

                      a = $10,000       b = $15,000

Find:-

Suppose you bid $12,000. What is the probability that your bid will be accepted?

Solution:-

- We will denote a random variable X that defines the bid placed being accepted. The variable X follows a uniform distribution with parameters [a,b].

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- The probability of $12,000 bid being accepted can be determined by the cdf function of the uniform distribution, while the pmf is as follows:

                                Pmf = 1 / ( b - a )

                                Pmf = 1 / ( 15,000 - 10,000 )

                                Pmf = 1 / ( 5,000 )

                                cdf = \int\limits^x_a {\frac{1}{5000} } \, dy \\\\cdf =  {\frac{y}{5000} }\limits^x_a \\\\P(X

6 0
3 years ago
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