After the addition of 6.47 mL of 0.303 M HCl. Solution :- lets first calculate the moles of the NaOCl and HCl Moles = molarity *volume in liter Moles of NaOCl = 0.100 mol per L * 0.053 L =0.0053 mol Moles of HCl =0.303 mol per L *0.00647L=0.00196
Answer:
1. How many ATOMS of boron are present in 2.20 moles of boron trifluoride? atoms of boron.
2. How many MOLES of fluorine are present in of boron trifluoride? moles of fluorine.
Explanation:
The molecular formula of boron trifluoride is 
.
So, one mole of boron trifluoride has one mole of boron atoms.
1. The number of boron atoms in 2.20 moles of boron trifluoride is 2.20 moles.
The number of atoms in 2.20 moles of boron is:
One mole of boron has ---- 
atoms.
Then, 2.20 moles of boron has
-
2. Calculate the number of moles of BF3 in 5.35*1022 molecules.
One mole of boron trifluoride has three moles of fluorine atoms.
Hence, 0.0888moles of BF3 has 3x0.0888mol of fluorine atoms.
=0.266mol of fluorine atoms.
Answer:
A mole is the amount of pure substance containing the same number of chemical units as there are atoms in exactly
12 grams of carbon-12 (i.e., 6.023 X 1023).
Explanation:
Answer:
9.93
Explanation:
Your value for Kw is incorrect. The correct value is 5.48 × 10^-14.
pH + pOH = pKw
3.30 + pOH = -log(5.84 × 10^-14) = 13.23
pOH = 13.23 - 3.30 = 9.93
The pOH of the solution is 9.93.
To determine the expected pH of the resulting solution of the following substances, create a balanced chemical equation of their ionization in water:
HI
HI + H2O ---> H+ + I-
It completely dissociates into H+ and I-. Due to the presence of the Hydronium Ion, the solution is acidic.
KBr
KBr + H2O ----> HBr + KOH
The salt KBr is formed by a strong base and a weak acid, therefore, the solution it forms with water is basic.
LiOH
LiOH + H2O ----> Li+ + OH-
It dissociates completely in water, turns into Li+ and OH-. Due to the presence of Hydroxide Ion, the solution becomes basic.
