One of the following substances would be the most soluble in CCl₄ is C₄H₁₀.
<h3>What is CCl₄?</h3>
CCl₄ is carbon tetra chloride is an organic compound with a sweet smell and colorless liquid.
It is used in liquid for refrigerator, as a pesticide, a propellant for aresol cans and in fire extinguisher, but it is very a harmful substance that why it is banned.
Thus, the substances would be the most soluble in CCl₄ is C₄H₁₀.
Learn more about carbon tetra chloride
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Answer:
15.5 km
Explanation:
1.55 x 10^4 m means 1.55 x 10000 = 15,500 m
1 km = 1000 meters
To convert to km we divide by 1000
So 15,500/1000
= 15.5 km
Answer: The empirical formula is 
Explanation:
If percentage are given then we are taking total mass is 100 grams.
So, the mass of each element is equal to the percentage given.
Mas of H = 1.8 g
Mass of S = 56.1 g
Mass of O = 42.1 g
Step 1 : convert given masses into moles.
Moles of H =
Mass of S =
Moles of O=
Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.
For H =
For S =
For O =
Converting to whole number ratios
The ratio of H: S: O= 2: 2: 3
Hence the empirical formula is 
Answer:
8.937g/cm³
Explanation:
To answer this question we need to know that, in 1 unit FCC cell you have:
Edge length = √8 * R
<em>Volume = 8√8 * R³</em>
<em>And there are 4 atoms per unit cell</em>
<em />
<em>Mass of 4 atoms in g:</em>
4 atom * (1mol / 6.022x10²³atom) * (63.55g / mol) = 4.221x10⁻²²g
<em />
<em>Volume in cm³:</em>
0.1278nm * (1x10⁻⁷cm / 1nm) = 1.278x10⁻⁸cm
Volume = 8√8 * (1.278x10⁻⁸cm)³
Volume = 4.723x10⁻²³cm³
And density is:
4.221x10⁻²²g / 4.723x10⁻²³cm³ =
<h3>8.937g/cm³</h3>