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Vinil7 [7]
3 years ago
11

Calculate the number of atoms in a 3.96 × 103 g sample of silicon.

Chemistry
1 answer:
Crank3 years ago
6 0
Atomic mass Si = 28.0855 u.m.a

28.0855 g -------------------- 6.02x10²³ atoms
3.96x10³ g ------------------- ?? atoms

( 3.96x10³) x 6.02x10²³ / 28.0855 =

8.48x10²⁵ atoms




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Which one of the following substances would be the most soluble in ccl4?
mezya [45]

One of the following substances would be the most soluble in CCl₄ is C₄H₁₀.

<h3>What is CCl₄?</h3>

CCl₄ is carbon tetra chloride is an organic compound with a sweet smell and colorless liquid.

It is used in liquid for refrigerator, as a pesticide, a propellant for aresol cans and in fire extinguisher, but it is very a harmful substance that why it is banned.

Thus, the substances would be the most soluble in CCl₄ is C₄H₁₀.

Learn more about carbon tetra chloride

brainly.com/question/3102041

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7 0
3 years ago
How do you solve this?4. How many km are equal to 1.55 x 10^4 m?
katrin [286]

Answer:

15.5 km

Explanation:

1.55 x 10^4 m means 1.55 x 10000 = 15,500 m

1 km = 1000 meters

To convert to km we divide by 1000

So 15,500/1000

= 15.5 km

4 0
3 years ago
A laboratory analysis of a 100 g sample finds it is composed of 1.8 g hydrogen, 56.1 g sulfur, and 42.1 g oxygen. What is its em
Neporo4naja [7]

Answer: The empirical formula is H_2S_2O_3

Explanation:

If percentage are given then we are taking total mass is 100 grams.

So, the mass of each element is equal to the percentage given.

Mas of H = 1.8 g

Mass of S = 56.1 g

Mass of O = 42.1 g

Step 1 : convert given masses into moles.

Moles of H =\frac{\text{ given mass of H}}{\text{ molar mass of H}}= \frac{1.8g}{1g/mole}=1.8moles

Mass of S =\frac{\text{ given mass of S}}{\text{ molar mass of S}}= \frac{56.1g}{32g/mole}=1.8moles

Moles of O=\frac{\text{ given mass of O}}{\text{ molar mass of O}}= \frac{42.1g}{16g/mole}=2.6moles

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For H = \frac{1.8}{1.8}=1

For S = \frac{1.8}{1.8}=1

For O =\frac{2.6}{1.8}=1.5

Converting to whole number ratios

The ratio of H: S: O= 2: 2: 3

Hence the empirical formula is H_2S_2O_3

7 0
3 years ago
Calculate the theoretical density (in g/cm3) of copper (Cu), given that it has the FCC structure. The atomic weight of Cu is 63.
sasho [114]

Answer:

8.937g/cm³

Explanation:

To answer this question we need to know that, in 1 unit FCC cell you have:

Edge length = √8 * R

<em>Volume = 8√8 * R³</em>

<em>And there are 4 atoms per unit cell</em>

<em />

<em>Mass of 4 atoms in g:</em>

4 atom * (1mol / 6.022x10²³atom) * (63.55g / mol) = 4.221x10⁻²²g

<em />

<em>Volume in cm³:</em>

0.1278nm * (1x10⁻⁷cm / 1nm) = 1.278x10⁻⁸cm

Volume = 8√8 * (1.278x10⁻⁸cm)³

Volume = 4.723x10⁻²³cm³

And density is:

4.221x10⁻²²g / 4.723x10⁻²³cm³ =

<h3>8.937g/cm³</h3>

6 0
4 years ago
What is the measure if how much space an object takes up? A. Mass B. Density C. Weight D. Volume
givi [52]

Answer:

volume

Explanation:

8 0
3 years ago
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