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GalinKa [24]
4 years ago
13

When is the only time that an object has no kinetic energy?

Physics
2 answers:
Lelu [443]4 years ago
3 0

Answer:

Drew macintyre

Explanation:

u%xhhhuer+Hiuijjjdhfdujdjdjihsuwidhususususgdususeusdofur

Vera_Pavlovna [14]4 years ago
3 0

Answer:

The only time an object has NO kinetic energy is when the velocity is "Zero"

Explanation:

The object starts out with no kinetic energy and potential energy of PE = mgh where m is the mass.The kinetic energy is zero. As the object falls it loses potential energy and gains kinetic energy KE = mv2/2.

Hope I help you

(You should totally give me a Brainllest!)

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You exit the Vet's Office.
kifflom [539]

(1) When you exit the office, your position is 60.8 m and the total distance traveled is 60.8 m.

(2) When you walk to the bank, your position is 60.8 m, displacement is 0 and the total distance traveled is 121.6 m.

(3) When you walk to flower shop, your position is 26.9 m, displacement is 0 and the total distance traveled is 148.5 m.

(4) When you walk to the Vet's Office, your position is 60.8 m, displacement is 60.8 m and the total distance traveled is 182.4 m.

<h3>You exit the Vet's Office</h3>

When you exit the Vet's Office, your position is 60.8 m (assuming your starting position is the bank).

The total distance have you travelled = 26.9 m + 33.9 m = 60.8 m

<h3>You walk to the Bank</h3>

your new position is 60.8 m

your displacement = 60.8 m - 60.8 m = 0 (assuming your starting position is the bank)

total distance have you travelled = 60.8 m +  60.8 m = 121.6 m

<h3>You walk to the Flower Shop</h3>

your new position is 26.9 m

your total displacement = 0 + 26.9 m = 26.9 m

total distance have you travelled = 26.9 m + 121.6 m = 148.5 m

<h3>You walk to the Vet's Office</h3>

your new position is 26.9 m + 33.9 m = 60.8 m

your total displacement = 26.9 m + 33.9 m = 60.8 m

total distance have you travelled = 148.5 m + 33.9 m = 182.4 m

Learn more about displacement here: brainly.com/question/2109763

#SPJ1

5 0
2 years ago
Calculate the ratio of the resistance of 12.0 m of aluminum wire 2.5 mm in diameter, to 30.0 m of copper wire 1.6 mm in diameter
alukav5142 [94]

Answer: 0.258

Explanation:

The resistance R of a wire is calculated by the following formula:

R=\rho\frac{l}{s}    (1)

Where:

\rho is the resistivity of the material the wire is made of. For aluminium is \rho_{Al}=2.65(10)^{-8}m\Omega  and for copper is \rho_{Cu}=1.68(10)^{-8}m\Omega

l is the length of the wire, which in the case of aluminium is l_{Al}=12m, and in the case of copper is l_{Cu}=30m

s is the transversal area of the wire. In this case is a circumference for both wires, so we will use the formula of the area of the circumference:

s=\pi{(\frac{d}{2})}^{2}  (2) Where d  is the diameter of the circumference.

For aluminium wire the diameter is  d_{Al}=2.5mm=0.0025m  and for copper is d_{Cu}=1.6mm=0.0016m

So, in this problem we have two transversal areas:

<u>For aluminium:</u>

s_{Al}=\pi{(\frac{d_{AL}}{2})}^{2}=\pi{(\frac{0.0025m}{2})}^{2}

s_{Al}=0.000004908m^{2}   (3)

<u>For copper:</u>

s_{Cu}=\pi{\frac{(d_{Cu}}{2})}^{2}=\pi{(\frac{0.0016m}{2})}^{2}

s_{Cu}=0.00000201m^{2}    (4)

Now we have to calculate the resistance for each wire:

<u>Aluminium wire:</u>

R_{Al}=2.65(10)^{-8}m\Omega\frac{12m}{0.000004908m^{2}}     (5)

R_{Al}=0.0647\Omega     (6)  Resistance of aluminium wire

<u>Copper wire:</u>

R_{Cu}=1.68(10)^{-8}m\Omega\frac{30m}{0.00000201m^{2}}     (6)

R_{Cu}=0.250\Omega     (7)  Resistance of copper wire

At this point we are able to calculate the  ratio of the resistance of both wires:

Ratio=\frac{R_{Al}}{R_{Cu}}   (8)

\frac{R_{Al}}{R_{Cu}}=\frac{0.0647\Omega}{0.250\Omega}   (9)

Finally:

\frac{R_{Al}}{R_{Cu}}=0.258  This is the ratio

3 0
4 years ago
If the wavelength of a wave of light is 4.57x10^-9 m what is the frequency
alexandr402 [8]

Answer:

6.5646\times 10^{16}~ \text{Hz}

Explanation:

\text{Frequency,}~ f= \dfrac{c}{\lambda} = \dfrac{3\times 10^8 }{4.57 \times 10^{-9}} = 6.5646\times 10^{16}~ \text{Hz}

5 0
3 years ago
Lumbar nerves transmit signals that allow us to?
labwork [276]
Lumbar nerves transmit signals that allow us to walk. They are a pivotal part of the human body, and without them we would be immobile. Hope this helps.
7 0
4 years ago
Read 2 more answers
If the gradient of an Extension versus Force graph was found to be 5.6, then what is the value of the spring constant? *
worty [1.4K]

Answer:

5.6

Explanation:

F=kx is the formula for spring force.  If Extension versus Force was graphed, a linear relation would appear, where the slope is the k value, aka the spring constant.

5 0
3 years ago
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