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PIT_PIT [208]
3 years ago
12

Lumbar nerves transmit signals that allow us to?

Physics
2 answers:
labwork [276]3 years ago
7 0
Lumbar nerves transmit signals that allow us to walk. They are a pivotal part of the human body, and without them we would be immobile. Hope this helps.
Marina86 [1]3 years ago
3 0

Answer:

walk is the correct answer :)

Explanation:

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Which one of the following acid-base imbalances? Arterial blood gas levels are obtained from the client. If the client’s results
nekit [7.7K]

Answer:

Explanation:

The correct answer is Metabolic alkalosis (D). A pH of 7.48 shows slight alkalinity, this normal concentration of Co2 in the blood ranges from 35 mmHg (millimetre Mercury) to 45 mmHg and the normal HCo3 ( Hydrogen trioxo carbonate ion) concentration ranges from 22mEq/L to 26mEq/L.

Therefor the patients pH level is high the Co2 level is normal and the HCo3 level is high. Hence, Metabolic alkalosis

7 0
3 years ago
You find an unmarked blue laser on your way to physics class. When you get to class you realize you can determine the wavelength
Afina-wow [57]

Answer:

λ = 451.7 nm

Explanation:

The expression for the constructive interference of the double diffraction experiment is

          d sin θ = m λ

let's use trigonometry

          tan θ = y / L

   

how the experiment occurs at very small angles

          tan θ = sin θ / cos θ = sin θ

          sin θ = y / L

we substitute

         d y / L = m λ  

         λ = \frac{d \ y}{m \ L}

let's calculate

          λ = \frac{0.342 \ 10^{-3} \ 2.80 \ 10^{-3} }{1 \ 2.12 }

          λ = 4.51699 10⁻⁷ m

          λ = 4.517 10⁻⁷ m (109 nm / 1m)

          λ = 451.7 nm

5 0
3 years ago
21. If the Sun's rays were at 45° to a vertical pillar, how would
diamong [38]

Answer:

Let the height of the pole AB = x m. ∴ Length of shadow OB ol the pole AB = x m. Let the angle of elevation be ө, i.e. Hence, the angle of elevation of the Sun's altitude is 45°.

Explanation:

4 0
3 years ago
A long uniformly charged thread (linear charge density λ= 2.5 C/m) lies along the x axis in the figure.(Figure 1) A small charge
Kamila [148]

Answer 1) The electric field at distance r from the thread is radial and has magnitude  

E = λ / (2 π ε° r)  

The electric field from the point charge usually is observed to follow coulomb's law:  

E = Q / (4  π ε° r^{2})  

Now, adding the two field vectors:  

E_{thread}  =  {2.5 / (22 π ε° X 0.07 ) ; 0}  

Answer 2) E_{q}  = {2.3 / (4 2 π ε°) ( - 7/ (√(84); -12 / (√84))

Adding these two vectors will give the length which is magnitude of the combined field.  

The y-component / x-component gives the tangent of the angle with the positive x-axes.

Please refer the graph and the attachment for better understanding.

5 0
3 years ago
An 87.6 g lead ball is dropped from rest from a height of 7.00 m. The collision between the ball and the ground is totally inela
bija089 [108]

Taking specific heat of lead as 0.128 J/gK = c

We have energy of ball at 7.00 meter height = mgh = 87.6*10^{-3}*9.81*7

When leads gets heated by a temperature ΔT energy needed = mcΔT

                                                                      = 87.6*10^{-3}*0.128*10^3ΔT

Comparing both the equations

                      87.6*10^{-3}*9.81*7 = 87.6*10^{-3}*0.128*10^3ΔT

                        ΔT = 0.536 K

                        Change in temperature same in degree and kelvin scale

                                      So ΔT = 0.536 ^0C

7 0
3 years ago
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