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3 years ago

What is: X/6+4=15 In simplest form?

1 answer:

defon3 years ago

5 0

X/6+4=15
subtract 4 from both sides to get rid of the addition
x/6=11
multiply by 6 from both sides to get rid of the division
x=66(simplest form)

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PLEASE HELP FAST

IceJOKER [234]

-4,-9 I took the test and got the same answer.

3 0

3 years ago

Write the expression 17 4/3 using radicals :)

bixtya [17]

Convert to radical form using the formula
a
x
n
=
n
√
a
x
a
x
n
=
a
x
n
.
Exact Form:
3
√
17
4
17
4
3
Decimal Form:
43.71178704
I’m so sorry it won’t let me type it right on my phone but hope this helps

6 0

3 years ago

Find the area of a triangle with legs that are 9mm 6mm and 12mm

Sidana [21]

Here we are given the three sides of the triangle.

So we have Heron's formula to find its area.

Heron's formula is given by :

$A= \sqrt{S(S-A)(S-B)(S-C)}$

where A, B and C are sides of triangle and S is semi perimeter which is given by,

$S= \frac{A+B+C}{2}$

plugging values of A, B and C to find S

$S= \frac{9+6+12}{2}$

S=13.5

Now plugging values of A, B , C and S in Heron's formula

$A= \sqrt{13.5(13.5-9)(13.5-6)(13.5-12)}$

A=26.14 mm²

Answer: Area of triangle is 26.14 mm².

6 0

3 years ago

Figure 1 is transformed to Figure 3, as shown in the diagram. Describe the transformation. A) dilation, then reflection B) refle

tresset_1 [31]

C. hope this helps...

3 0

3 years ago

Read 2 more answers

What is the solution to sqrt 17-x=x+3? Show your work.

snow_lady [41]

Answer:

$x=1$

Step-by-step explanation:

Remember:

$(\sqrt[n]{a})^n=a\\\\(a+b)=a^2+2ab+b^2$

Given the equation $\sqrt{17-x}=x+3$ , you need to solve for the variable "x" to find its value.

You need to square both sides of the equation:

$(\sqrt{17-x})^2=(x+3)^2$

$17-x=(x+3)^2$

Simplifying, you get:

$17-x=x^2+2(x)(3)+3^2\\\\17-x=x^2+6x+9\\\\x^2+6x+9+x-17=0\\\\x^2+7x-8=0$

Factor the quadratic equation. Find two numbers whose sum be 7 and whose product be -8. These are: -1 and 8:

$(x-1)(x+8)=0$

Then:

$x_1=1\\x_2=-8$

Let's check if the first solution is correct:

$\sqrt{17-(1)}=(1)+3$

$4=4$ (It checks)

Let's check if the second solution is correct:

$\sqrt{17-(-8)}=(-8)+3$

$5\neq-5$ (It does not checks)

Therefore, the solution is:

$x=1$

3 0

3 years ago