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ale4655 [162]
3 years ago
6

Evaluate 0.1m + 8 - 12n when m = 30 and n = 1/4

Mathematics
1 answer:
Sladkaya [172]3 years ago
7 0
We simply substitute the given values into the expression

0.1(30)+8-12(1/4)

Which is 8
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3,6

Step-by-step explanation:

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Helppppppppppppp plsssssssssssssssss
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PQR = 40

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What is the height of an equilateral triangle with side lengths of 14?
olganol [36]
If Each side of an equilateral triangle<span> is 10 m. ... Thus </span>triangle<span> APC is a right</span>triangle<span>. The length of CA is 10 m, and the length of PC is 5 m, and hence you can use Pythagoras' theorem to find the length of AP, which </span>is the height<span> of the </span>triangle<span>ABC.
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5 0
4 years ago
Read 2 more answers
Write a formula that will help Eric determine how much the potatoes he buys will costs in bulk
Evgesh-ka [11]
T=K*P
The total cost (T) equals the amount of kilograms (K) multiplied by the price per kilogram (P).

7 0
3 years ago
HELP PLEASE IT EASY! <br> + no files please!!
NARA [144]

Answer:

<u>GIVEN :-</u>

Ordered pairs given are :-

  • (2 , -1)
  • (-5 , 3)
  • (4 , 3)
  • (-2 , -3.5)
  • (0.5 , 1.75)

<u>TO FIND :-</u>

  • Correct quadrant for each ordered pair.

<u>FACTS TO KNOW BEFORE SOLVING :-</u>

  • While writing the co-ordinates of a point , its ordered pair is always in the form of ( x , y ) where x = x-coordinate of the point & y = y-coordinate of the point.
  • In Quadrant 1 , the coordinates of a point is always = ( +x , +y ) because Quadrant 1 lies between the positive side of x-axis & positive side of y-axis.
  • In Quadrant 2 , the coordinates of a point is always = ( -x , +y ) because Quadrant 2 lies between the negative side of x-axis & positive side of y-axis.
  • In Quadrant 3 , the coordinates of a point is always = ( -x , -y ) because Quadrant 3 lies between the negative side of x-axis & negative side of y-axis.
  • In Quadrant 4 , the coordinates of a points is always = ( +x , -y ) because Quadrant 4 lies between the positive side of x-axis & negative side of y-axis.

<u>SOLUTION :-</u>

  • (2 , -1) is in <u>Quadrant 4</u> because it's x-coordinate is positive whereas its y-coordinate is negative.
  • (-5 , 3) is in <u>Quadrant 2</u> because its x-coordinate is negative but y-coordinate is positive.
  • (4 , 3) is in <u>Quadrant 1</u> because both its x-coordinates & y-coordinates are positive.
  • (-2 , -3.5) is in <u>Quadrant 3</u> because both its x-coordinates & y-coordinates are negative.
  • (0.5 , 1.75) is in <u>Quadrant 1</u> because both its x-coordinates & y-coordinates are positive.
7 0
3 years ago
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