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Mariulka [41]
3 years ago
11

Five expressions that are equivalent to 20x + 18

Mathematics
1 answer:
jonny [76]3 years ago
7 0

1) 10x + 9

2) 40x + 36

3) 60x + 54

4) 80x + 72

5) 100x + 90

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Water is added to a cylindrical tank of radius 5 m and height of 10 m at a rate of 100 L/min. Find the rate of change of the wat
nirvana33 [79]

Answer:

V = \pi r^2 h

For this case we know that r=5m represent the radius, h = 10m the height and the rate given is:

\frac{dV}{dt}= \frac{100 L}{min}

Q = 100 \frac{L}{min} *\frac{1m^3}{1000L}= 0.1 \frac{m^3}{min}

And replacing we got:

\frac{dh}{dt}=\frac{0.1 m^3/min}{\pi (5m)^2}= 0.0012732 \frac{m}{min}

And that represent 0.127 \frac{cm}{min}

Step-by-step explanation:

For a tank similar to a cylinder the volume is given by:

V = \pi r^2 h

For this case we know that r=5m represent the radius, h = 10m the height and the rate given is:

\frac{dV}{dt}= \frac{100 L}{min}

For this case we want to find the rate of change of the water level when h =6m so then we can derivate the formula for the volume and we got:

\frac{dV}{dt}= \pi r^2 \frac{dh}{dt}

And solving for \frac{dh}{dt} we got:

\frac{dh}{dt}= \frac{\frac{dV}{dt}}{\pi r^2}

We need to convert the rate given into m^3/min and we got:

Q = 100 \frac{L}{min} *\frac{1m^3}{1000L}= 0.1 \frac{m^3}{min}

And replacing we got:

\frac{dh}{dt}=\frac{0.1 m^3/min}{\pi (5m)^2}= 0.0012732 \frac{m}{min}

And that represent 0.127 \frac{cm}{min}

5 0
4 years ago
If a right triangle has a hypotenuse of 13 inches and a leg of 5 inches, how could you use the Pythagorean Theorem to find the m
zaharov [31]
12,5,13 are Pythagorean triplets..

so, missing side will be 12 inches

hope it helps


Hyp^2 = Base^2 + perpendicular^2
4 0
3 years ago
Read 2 more answers
Please Help Me ASAP I Need <br> This For My grade
mel-nik [20]

Answer:

\huge slope \: of \: the \: graph =  \tan( \alpha )  =  \frac{perpendicular}{base}  =  \frac{(value\:of\: y-axis)}{(value\:of\:x-axis)}  =  \frac{1}{ - 1}  =  - 1

<h2>-1 is the right answer.</h2>
5 0
3 years ago
45^2 ÷ 78 = ????????
elena55 [62]
\frac{(45)^2}{78}

To solve the problem find the value of (45)^2 at first

(45)^2=2025\frac{2025}{78}=25\text{ R75}

The answer is 25 with the remainder 75

25\frac{75}{78}

You can simplify the fraction to be 25/26

25\frac{25}{26}

3 0
1 year ago
What is the area of the following trapezoid
nignag [31]

Answer:

d. 130

Step-by-step explanation:

3 0
3 years ago
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