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gavmur [86]
3 years ago
10

What is the height of an equilateral triangle with side lengths of 14?

Mathematics
2 answers:
Zina [86]3 years ago
6 0
<span>So it's length would be half of the length of the base </span>\frac{14}{2} = 7 <span>=> </span>7^{2} + x^{2} = 14^{2} => 49 +  = 196 => x^2 = 147 => x = sqrt 147 = 7 * sqrt 3 . So the altitude is equal to 7 * sqrt 3. An approximate value to that would be 12.12

Hope this helps
olganol [36]3 years ago
5 0
If Each side of an equilateral triangle<span> is 10 m. ... Thus </span>triangle<span> APC is a right</span>triangle<span>. The length of CA is 10 m, and the length of PC is 5 m, and hence you can use Pythagoras' theorem to find the length of AP, which </span>is the height<span> of the </span>triangle<span>ABC.
</span>If Each side of an equilateral triangle<span> is 10 m. ... Thus </span>triangle<span> APC is a right</span>triangle<span>. The length of CA is 10 m, and the length of PC is 5 m, and hence you can use Pythagoras' theorem to find the length of AP, which </span>is the height<span> of the </span>triangleABC. 
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2x = 15 + x

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Answer: \fbox { x = 15 }
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