Question

What is the height of an equilateral triangle with side lengths of 14?

Answer 1

So it's length would be half of the length of the base $\frac{14}{2}$ = 7 => $7^{2}$ + $x^{2}$ = $14^{2}$ => 49 +  = 196 => x^2 = 147 => x = sqrt 147 = 7 * sqrt 3 . So the altitude is equal to 7 * sqrt 3. An approximate value to that would be 12.12

Hope this helps

Answer 2

If Each side of an equilateral triangle is 10 m. ... Thus triangle APC is a righttriangle. The length of CA is 10 m, and the length of PC is 5 m, and hence you can use Pythagoras' theorem to find the length of AP, which is the height of the triangleABC.
If Each side of an equilateral triangle is 10 m. ... Thus triangle APC is a righttriangle. The length of CA is 10 m, and the length of PC is 5 m, and hence you can use Pythagoras' theorem to find the length of AP, which is the height of the triangleABC.