<span>So it's length would be half of the length of the base </span> = 7 <span>=> </span> + = => 49 + = 196 => x^2 = 147 => x = sqrt 147 = 7 * sqrt 3 . So the altitude is equal to 7 * sqrt 3. An approximate value to that would be 12.12
If Each side of an equilateral triangle<span> is 10 m. ... Thus </span>triangle<span> APC is a right</span>triangle<span>. The length of CA is 10 m, and the length of PC is 5 m, and hence you can use Pythagoras' theorem to find the length of AP, which </span>is the height<span> of the </span>triangle<span>ABC. </span>If Each side of an equilateral triangle<span> is 10 m. ... Thus </span>triangle<span> APC is a right</span>triangle<span>. The length of CA is 10 m, and the length of PC is 5 m, and hence you can use Pythagoras' theorem to find the length of AP, which </span>is the height<span> of the </span>triangleABC.
It form a right triangle legnth of ladder is hypotonuse bottom of ladder from wall distance is one leg distance up wall is other leg a^2+b^2=c^2 c=hypotonuse and a and b are legs
4^2+b^2=20^2 16+b^2=400 minus 16 both sides b^2=384 sqrt both sides b=8√6 ft aprox b=19.59ft from ground
