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Elza [17]
4 years ago
14

Solve for z. -11≤2z–3<9

Mathematics
1 answer:
Sav [38]4 years ago
4 0
-11\leq2z-3 < 9\ \ \ |+3\\\\-8\leq2z < 12\ \ \ |:2\\\\-4\leq z < 6

Answer:\ \boxed{-4\leq z < 6\to z\in\left(-\infty;-4\right>\ \cup\ (6;\ \infty)}
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