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ohaa [14]
3 years ago
7

ellie brought s sponges there were 10 sponges in each package write an expression that shows how many packages ellie brought

Mathematics
2 answers:
AleksandrR [38]3 years ago
5 0
You multiply s by the number of sponges 
In-s [12.5K]3 years ago
3 0
S x 10. S stands for the packages of sponges, and 10 stands for the number of sponges in each package. I hope this helps!
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Two cars leave towns 750 kilometers at the same time and travel toward each other. One car's rate is 12 kilometers per hour less
andreev551 [17]

If the distance between the two twons equals 750 km, and the cars met at some point on the road then the distance of the first car added to the distance of the second car equals 750 km, like this:

d1 + d2 = 750

Where d1 is the driven distance by the first car and d2 is the driven distance by the second car.

Distance, is the product of speed and time, then we can rewrite the above equation like this:

s1×t + s2×t = 750

S1 is the speed of the first car and s2 is the speed of the second time, t is the time. We already know that the time it took the cars to meet each other equals 5 hours, then, by replacing 5 for t into the above expression, we get:

s1×5 + s2×5 = 750

5(s1 + s2) = 750

We are also told that the speed of the first car is 12 less than the speed of the second car, this means that the speed of the first car equals the speed of the second one minus twelve. Then we can formulate the following expression for the speeds of the cars:

s1 = s2 - 12

By replacing s2 - 12 for s1 into 5(s1 + s2) = 750 we get:

5(s1 + s2) = 750

5(s2 - 12 + s2) = 750

5(s2 + s2 - 12) = 750

5(2s2 - 12) = 750

By dividing both sides by 5, we get:

(2s2 - 12) = 750/5

2s2 - 12 = 150

By adding 12 on both sides:

2s2 = 150 + 12

2s2 = 162

Finally, by dividing by 2 on both sides:

s2 = 162/2

s2 = 81

Now that we know that the speed of the second car, equals 81, we can find the speed of the first car by means of the formula s1 = s2 - 12, then we get:

s1 = s2 - 12

s1 = 81 - 12

s1 = 69

Then, the speed of the slower car equals 69 kilometers per hour

7 0
1 year ago
Please assist me in my time of need.
vaieri [72.5K]

Answer:

I shall assist thee.

Step-by-step explanation:

Being me, I would say the answer is A. or B. But i'd prolly go with A tbh.

And oofers on me if this ain't what you need.

4 0
3 years ago
Given tanθ = 8, find csc(θ)
In-s [12.5K]
Cosecθ=sq.rt of 65/8. hope it will help you
4 0
3 years ago
Read 2 more answers
8) Find the endpoint Cif M is the midpoint of segment CD and M (2, 4) and D (5,7)
Elenna [48]

Answer:

8. c. (-1, -1)

9. a. (-6, -1)

b. True

Step-by-step Explanation:

8. Given the midpoint M(2, 4), and one endpoint D(5, 7) of segment CD, the coordinate pair of the other endpoint C, can be calculated as follows:

let D(5, 7) = (x_2, y_2)

C(?, ?) = (x_1, y_1)

M(2, 4) = (\frac{x_1 + 5}{2}, \frac{y_1 + 7}{2})

Rewrite the equation to find the coordinates of C

2 = \frac{x_1 + 5}{2} and 4 = \frac{y_1 + 7}{2}

Solve for each:

2 = \frac{x_1 + 5}{2}

2*2 = \frac{x_1 + 5}{2}*2

4 = x_1 + 5

4 - 5 = x_1 + 5 - 5

-1 = x_1

x_1 = -1

4 = \frac{y_1 + 7}{2}

4*2 = \frac{y_1 + 7}{2}*2

8 = y_1 + 7

8 - 7 = y_1 + 7 - 7

1 = y_1

y_1 = 1

Coordinates of endpoint C is (-1, 1)

9. a.Given segment AB, with midpoint M(-4, -5), and endpoint A(-2, -9), find endpoint B as follows:

let A(-2, -9) = (x_2, y_2)

B(?, ?) = (x_1, y_1)

M(-4, -5) = (\frac{x_1 + (-2)}{2}, \frac{y_1 + (-9)}{2})

-4 = \frac{x_1 - 2}{2} and -5 = \frac{y_1 - 9}{2}

Solve for each:

-4 = \frac{x_1 - 2}{2}

-4*2 = \frac{x_1 - 2}{2}*2

-8 = x_1 - 2

-8 + 2 = x_1 - 2 + 2

-6 = x_1

x_1 = -6

-5 = \frac{y_1 - 9}{2}

-5*2 = \frac{y_1 - 9}{2}*2

-10 = y_1 - 9

-10 + 9 = y_1 - 9 + 9

-1 = y_1

y_1 = -1

Coordinates of endpoint B is (-6, -1)

b. The midpoint of a segment, is the middle of the segment. It divides the segment into two equal parts. The answer is TRUE.

4 0
3 years ago
What's the value of c that makes 9x^2 + 12x + c a perfect square trinomial.
seraphim [82]
The value of c that makes up a perfect square trinomial is


9x^2 - 12x +c
4 0
3 years ago
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