For the given function, the domain is D : { x ≥ 7} and the range is R: { y ≥ 9}
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How to get the domain and range?</h3>
Here we have a square root, remember that the argument of the square root must be equal or larger than zero, so the domain is such that:
x - 7 ≥ 0.
Solving for x we get:
x ≥ 0 + 7
Then the domain is:
x ≥ 7
To get the range, we evaluate in the minimum of the domain:
f(7) = √(7 - 7) + 9 = 9
Then the range is the set of all values larger than 9, because the function is increasing.
So the range is R: y ≥ 9.
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Answer:
9=x
Step-by-step explanation:
Answer:
2.24 s
Step-by-step explanation:
Given:
Δy = 80 ft
v₀ = 0 ft/s
a = 32 ft/s²
Find: t
Δy = v₀ t + ½ at²
80 ft = (0 ft/s) t + ½ (32 ft/s²) t²
t = 2.24 s
Answer:
The correct answer is B) f(x)=|x| - 11
Step-by-step explanation:
All vertical shifts in absolute value equations can be added on to the end outside of the parenthesis. Since this is a downward shift, we make it negative.
