First, determine the number of computers that are needed for 924 students.
n = (924 students)(5 computers / 12 students)
n = 385 computers
Since, there are only 125 computers, the difference can be calculated.
d = 385 computers - 125 computers
d = 260 computers
Hence, 260 more computers are still needed.
Justify means plug answer in and verify
so distribute 8(3-7x)=24-56x
143=7+24-56x
143=31-56x
minus 31 both sides
112=-56x
divide both sides by -56
-2=x
justify
plug it back
143=7+8(3-7x)
143=7+8(3-7(-2))
143=7+8(3-(-14))
143=7+8(3+14)
143=7+8(17)
143=7+136
143=143
true
x=-2
-110x+40
You need to use the distributive property for this problem
You multiply 22x times -5 (which is -110x) and -8 times -5 (which is 40) to get -110x+40
Answer:
5
Step-by-step explanation:
5*20=100
Here is how you solve...
Q= 3a+5ac
take out the common variable.
Q= a(3+5c)
get A by its self so divide each side by (3+5c).
Q/a(3+5c)= a(3+5c)/(3+5c)
Q/a(3+5c)=A
So your answer is A= Q/a(3+5c)
hope that helped.
