The answer is 0 < x < infinity
14. 2x-1 = 0, x+7=0
x = 1/2, x = -7
15. x^2 + 3x - 10 = 0
(x + 5)(x - 2) = 0
x = -5, x = 2
16. x^2 - 25 = 0
(x-5)(x+5)
x = 5, x = -5
Answer:
The first one
Step-by-step explanation:
For the first choice, the binomial is multiplied by itself, so it will result in a perfect square trinomial.
You can solve this either just plain algebra or with the use of trigonometry.
In this case, we'll just use algebra.
So, if we let M be the the point that partitions the segment into a ratio of 3:2, we have this relation:
KM/ML = 3/2
KM = 1.5 ML
We also have this:
KL = KM + ML
Substituting KM,
KL = (3/2) ML + ML
KL = 2.5 ML
Using the distance formula and the given coordinates of the K and L, we get the length of KL
KL = sqrt ( (5-(-5)^2 + (1-(-4))^2 ) = 5 sqrt(5)
Since,
KL = 2.5 ML
Substituting KL,
ML = (1/2.5) KL = (1/2.5) 5 sqrt(5) = 2 sqrt(5)
Using again the distance formula from M to L and letting (x,y) as the coordinates of the point M
ML = 2 sqrt(5) = sqrt ( (5-x)^2 + (1-y)^2 ) [let this be equation 1]
In order to solve this, we need to find an expression of y in terms of x. We can use the equation of the line KL.
The slope m is:
m = (1-(-4))/(5-(-5) = 0.5
Using the general form of the linear equation:
y = mx +b
We substitue m and the coordinate of K or L. We'll just use K.
-5 = (0.5)(-4) + b
b = -1.5
So equation of the line is
y = 0.5x - 1.5 [let this be equation 2]
Substitute equation 2 to equation 1 and solving for x, we get 2 values of x,
x=1, x=9
Since 9 does not make sense (it does not lie on the line), we choose x=1.
Using the equation of the line, we get y which is -1.
So, we get the coordinates of point M which is (1,-1)
We have been given a right angled triangle, hypotenuse is known, and angle has been given. we need to find the adjacent side to the angle.
we use trigonometry ratios.
the ratio where we relate the hypotenuse and adjacent side is the cosine.
cos θ = adjacent side / hypotenuse
where θ = 39°
hypotenuse - 17 m
adjacent side - x
we need to solve for x
cos 39° = x / 17
cos 39° = 0.77
0.7771 = x/17
x = 0.7771 x 17
x = 13.21 m
distance from Roman's feet to the base of the pole is 13.21
