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3 years ago

If two triangles are congruent, then the six________parts are congruent.

Mathematics

1 answer:

dybincka [34]3 years ago

5 0

I think the answer is angles

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Complete the table for the given rule. Rule: y=2x

Contact [7]

9 - 18
5 - 10
1 - 2

Work —
First line:
y = 2 (9)
y = 18

Second line:
10 = 2x
5 = x

Third line:
y = 2 (1)
y = 2

4 0

2 years ago

Read 2 more answers

Solve each compound inequality 10m > 84

Mazyrski [523]

$▪▪▪▪▪▪▪▪▪▪▪▪▪ {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪$

let's solve :

$10m > 84$

$m > \dfrac{84}{10}$

$m > 8.4$

6 0

2 years ago

What was the rate of change between $65 and $65 Please help

Furkat [3]

Answer:

There is no change.

Step-by-step explanation:

8 0

2 years ago

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Find a compact form for generating functions of the sequence 1, 8,27,... , k^3

pantera1 [17]

This sequence has generating function

$F(x)=\displaystyle\sum_{k\ge0}k^3x^k$

(if we include $k=0$ for a moment)

Recall that for $|x|$ , we have

$\displaystyle\frac1{1-x}=\sum_{k\ge0}x^k$

Take the derivative to get

$\displaystyle\frac1{(1-x)^2}=\sum_{k\ge0}kx^{k-1}=\frac1x\sum_{k\ge0}kx^k$

$\implies\dfrac x{(1-x)^2}=\displaystyle\sum_{k\ge0}kx^k$

Take the derivative again:

$\displaystyle\frac{(1-x)^2+2x(1-x)}{(1-x)^4}=\sum_{k\ge0}k^2x^{k-1}=\frac1x\sum_{k\ge0}k^2x^k$

$\implies\displaystyle\frac{x+x^2}{(1-x)^3}=\sum_{k\ge0}k^2x^k$

Take the derivative one more time:

$\displaystyle\frac{(1+2x)(1-x)^3+3(x+x^2)(1-x)^2}{(1-x)^6}=\sum_{k\ge0}k^3x^{k-1}=\frac1x\sum_{k\ge0}k^3x^k$

$\implies\displaystyle\frac{x+4x^3+x^3}{(1-x)^4}=\sum_{k\ge0}k^3x^k$

so we have

$\boxed{F(x)=\dfrac{x+4x^3+x^3}{(1-x)^4}}$

5 0

3 years ago

7x+11 >5x-5 Can someone helpp

PSYCHO15rus [73]

Answer:

x>-8

Step-by-step explanation:

7x+11>5x-5

2x+11>-5

2x>-16

x>-8

the > sign acts like an equal sign :)

7 0

3 years ago

Read 2 more answers