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jok3333 [9.3K]
3 years ago
10

-Which expression represents the phrase "twenty-three less than a number"? (Think about this one!)

Mathematics
2 answers:
4vir4ik [10]3 years ago
4 0
I believe it would be D
hodyreva [135]3 years ago
3 0
The correct answer is I believe is d
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Yes im dumb but i pretty much missed my education of 7th and now im 8th personal reasons and i need to at least get my grades up
Diano4ka-milaya [45]

Answer:

1. A    

2. B      

3.  (-3.5 , -6) --- III

    (-4 , 0)------- x-axis

    (9 , -2)------- II

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7 0
3 years ago
Select TWO expressions from the list that have the same value.
avanturin [10]

Answer:

cos 67 and sin 23........

6 0
3 years ago
Calcula el radio de un cilindro que tiene 8 cm de altura y un volumen de 122 cm cúbicos
kondaur [170]

Answer:

\huge{ \boxed{ \sf{2.20 \: cm}}}

Step-by-step explanation:

\star{ \sf{ \:  altura  \: de \:  un \:  cilindro\:  =  \: 8 \: cm}}

\star{ \sf{ \: volumen  \: de  \: un  \: cilindro = 122  \: cm \:  cúbicos}} \:

\star {  \sf{ \: encontrar :radio   \: de  \: un  \:  cilindro }}

\boxed{ \sf{ \: Volume \: of \: a \: cylinder \:  =  \:  {\pi \: radius}^{2}  \: height}}

\mapsto{ \sf{122 \:  =  \: ( \frac{22}{7} )r \: ^{2}  \:  \times  \: 8}}

\mapsto{ \sf{122 = 25.14 \:  {r}^{2} }}

\mapsto{ \sf{25.14 \:  {r}^{2} = 122 }}

\mapsto{ \sf{ \frac{25.14 \:  {r}^{2} }{25.14}  =  \frac{122}{25.14}}}

\mapsto{ \sf{ {r}^{2} = 4.85 \: cm}}

\mapsto{ \sf{r = 2.20 \: cm}}

radio de un cilindro = 2.20 cm

\sf{espero  \: haber \:  ayudado!}

\sf{atentamente \:}!

~\sf{TheAnimeGirl}

5 0
3 years ago
8 minus the quotient of 15 and Y equals a product of Y and 13
meriva

Translating this verebal statement into a symbolic statement:

8 - 15/y = 13y.

Note: your statement would sound better if written as "8 minus the quotient of 15 and y equals the product of y and 13."

8 0
4 years ago
What is -2x – 10 = 4????
Sunny_sXe [5.5K]

Answer:

x = -7

Step-by-step explanation:

-2x - 10 = 4

-2x = 14 | Add 10 to both sides

x = -7 | Divide both sides by -2

4 0
3 years ago
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