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kati45 [8]
4 years ago
7

Factor x3 + 2x2 + x completely. a. (x+1)^2 b. x(x+1)^2 c. x(x+1)^2

Mathematics
1 answer:
enot [183]4 years ago
7 0

Option B

<u>ANSWER:  </u>

The factors of  $x^{3}+2 x^{2}+x$ is $x(x+1)^{2}$

<u>SOLUTION: </u>

Given, cubic expression is  $x^{3}+2 x^{2}+x$

Now, we have to find the factors of above equation.

To factorize the given equation, follow the below steps:

$\mathrm{x}^{3}+2 \mathrm{x}^{2}+\mathrm{x}$

Since x is common in every term of expression, we can take it as common

$x\left(x^{2}+2 x+1\right)$

“2x” can be rewritten as “x + x”, the above equation becomes,

$x\left(x^{2}+x+x+1\right)$

Taking the common terms out of bracket. we get

x(x (x + 1) + 1 (x + 1))  

Taking (x + 1) as common., we get

x ((x + 1)(x + 1))  

$x(x+1)^{2}$

Hence, the second option b is correct.

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Using permutation (since the ordering matters):

nPr = n! ÷(n-r)!

8P3 = 8! ÷ (8-3)!

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Using the combination relation :

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