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3 years ago

9

An envelope measures 8 inches by 15 inches. A pencil is placed in

2 answers:

UNO [17]3 years ago

5 0

Answer:

The length of the pencil is 17 inches.

Step-by-step explanation:

You need to do the Pythagorean theorem. For example, this is what I did, 8^2+15^2=x^2

64+225=x^2

289=x^2

the square root of 289 is 17.

hope this helps :)

Oliga [24]3 years ago

3 0

The length of the pencil would be 17. This could be easily found by using a^2 + b^2 = c^2. Please mark me brainliest it would be pretty cash money of you

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If there are 22 red cards and 28 black card, what is the probability you would draw a red card?

morpeh [17]

it would be 22/50 or 11/25

3 0

3 years ago

An automobile company wants to determine the average amount of time it takes a machine to assemble a car. A sample of 40 times y

aksik [14]

Answer:

A 98% confidence interval for the mean assembly time is [21.34, 26.49] .

Step-by-step explanation:

We are given that a sample of 40 times yielded an average time of 23.92 minutes, with a sample standard deviation of 6.72 minutes.

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

P.Q. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample average time = 23.92 minutes

s = sample standard deviation = 6.72 minutes

n = sample of times = 40

$\mu$ = population mean assembly time

<em> Here for constructing a 98% confidence interval we have used a One-sample t-test statistics because we don't know about population standard deviation. </em>

<u>So, a 98% confidence interval for the population mean, </u> $\mu$ <u> is; </u>

P(-2.426 < $t_3_9$ < 2.426) = 0.98 {As the critical value of z at 1% level

of significance are -2.426 & 2.426}

P(-2.426 < $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ < 2.426) = 0.98

P( $-2.426 \times {\frac{s}{\sqrt{n} } }$ < ${\bar X-\mu}$ < $2.426 \times {\frac{s}{\sqrt{n} } }$ ) = 0.98

P( $\bar X-2.426 \times {\frac{s}{\sqrt{n} } }$ < $\mu$ < $\bar X+2.426 \times {\frac{s}{\sqrt{n} } }$ ) = 0.98

<u>98% confidence interval for</u> $\mu$ = [ $\bar X-2.426 \times {\frac{s}{\sqrt{n} } }$ , $\bar X+2.426 \times {\frac{s}{\sqrt{n} } }$ ]

= [ $23.92-2.426 \times {\frac{6.72}{\sqrt{40} } }$ , $23.92+2.426 \times {\frac{6.72}{\sqrt{40} } }$ ]

= [21.34, 26.49]

Therefore, a 98% confidence interval for the mean assembly time is [21.34, 26.49] .

7 0

3 years ago

Distance time speed<br>

OLEGan [10]

Speed = Distance ÷ Time

3 0

3 years ago

Use the raw data below to create a table that can be used to create a histogram with 5

schepotkina [342]

Answer:

Five classes

Step-by-step explanation:

1. Sort the data

You get

1.1, 1.3, 1.6, 1.7, 2, 2.6, 2.7, 2.9, 3.2, 3.2, 3.5, 3.5, 3.9, 4.6, 4.7, 4.8, 4.8, 4.9, 4.9, 5.3, 5.7, 6.4, 6.5, 7.1, 7.5, 7.6, 8.1, 8.2, 9.2, 9.4

2. Calculate the range

Range = Max - Min = 9.4 - 1.1 = 8.3

3. Calculate the class width

Divide the range by the number of classes

8.3/5 = 1.7

Round this up to 2.

4. Decide where to start the histogram

You could use classes: 1 - 3, 3 - 5, 5 - 7, 7 - 9, 9 -11

However, even numbers are easier to read.

It would be preferable to use classes: 0 - 2, 2 - 4, 4 - 6, 6 - 8, 8 - 10

5. Prepare a frequency distribution table

Note: Each class does not include its largest possible value. Thus, a value of 2 goes into Class 2 - 4, (not Class 0 - 2).

$\begin{array}{cc}\textbf{Miles run} & \textbf{No. of students} \\0 - 2 & 4 \\2 - 4 & 9 \\4 - 6 & 8 \\6 - 8 & 5 \\8 - 10 & 4 \\\end{array}$

4 0

3 years ago

The average rate of change of a function f(x) = x2 between x = 3 and x = 9 is

masya89 [10]

Answer:

12.

Step-by-step explanation:

Average rate of change = (value of the function when x = 9 - value when x=3)

/

(9 - 3)

= f(9) - f(3) / (9-3)

= (9^2 - 3^2) / (9-3)

= 72 / 6

= 12.

6 0

3 years ago