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3 years ago

5

A pre-image was translated twice. The first translation moved the triangle left 2 units and up 5 units. The second translation f

ollowed the transformation rule (x, y) → (x − 4, y − 1). Write one transformation rule that combines the two translations into one translation

1 answer:

nlexa [21]3 years ago

7 0

Answer: I don’t know

Step-by-step explanation:

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Write each ratio in simplest form.1.1.4/7

horsena [70]

1.4 / 7

multiply by 10 in both up and down
(1.4*10) / (7*10)
14 / 70

divide by 7
(14/7) / (70/7)
2 / 10

divide by 2
(2/2) / (10/2)
1 / 5

3 0

3 years ago

What is 1/4 of 2,800

scZoUnD [109]

Answer:

700

Step-by-step explanation:

2800/4=700

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3 years ago

If a production line produces 50 mouse traps every 30 minutes over the course of a 10 hour work day with a half-hour break for l

stira [4]

The awnser is 1000 because 60 miutes in an hour, 50 mouse traps every half hour so 100 mouse traps an hour multiply that by 10 and you get 1000, i think.

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4 years ago

Read 2 more answers

Can someone help me out?

Lapatulllka [165]

502.7 is the answer!

8 0

3 years ago

How many students must be randomly selected to estimate the mean weekly earnings of students at one college? We want 95% confide

kari74 [83]

Answer:

The sample of students required to estimate the mean weekly earnings of students at one college is of size, 3458.

Step-by-step explanation:

The (1 - <em>α</em>)% confidence interval for population mean (<em>μ</em>) is:

$CI=\bar x\pm z_{\alpha/2}\times \frac{\sigma}{\sqrt{n}}$

The margin of error of a (1 - <em>α</em>)% confidence interval for population mean (<em>μ</em>) is:

$MOE=z_{\alpha/2}\times \frac{\sigma}{\sqrt{n}}$

The information provided is:

<em>σ</em> = $60

<em>MOE</em> = $2

The critical value of <em>z</em> for 95% confidence level is:

$z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96$

Compute the sample size as follows:

$MOE=z_{\alpha/2}\times \frac{\sigma}{\sqrt{n}}$

$n=[\frac{z_{\alpha/2}\times \sigma }{MOE}]^{2}$

$=[\frac{1.96\times 60}{2}]^{2}$

$=3457.44\\\approx 3458$

Thus, the sample of students required to estimate the mean weekly earnings of students at one college is of size, 3458.

8 0

3 years ago