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bearhunter [10]

3 years ago

11

A ferris wheel can accommodate 40 people in 30 minutes. How many people could ride the ferris wheel in 3 hours? What was that ra

te per hour

1 answer:

andrew-mc [135]3 years ago

3 0

240 people could ride it in 3 hours. The rate per hour is 80 people.

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GIven the function f(x) = 3x +1: (A) Find the inverse of f^-1(x). (B) Find f^-1(6)

Pani-rosa [81]

The inverse function is equal to f-1(x) = (x - 1)/3 and the value at f-1(6) is equal to 5/3.

To find the inverse, you need to switch the f(x) and x in the equation. Then you can solve for the new f(x). The result will be the inverse (f-1)

f(x) = 3x + 1 ----> Switch f(x) and x

x = 3f(x) + 1 ----> Subtract 1

x - 1 = 3f(x) ----> Divide by 3.

f-1(x) = (x - 1)/3

Now that we have the inverse, we can plug 6 in to get the value at f-1(6).

f-1(x) = (x - 1)/3

f-1(6) = (6 - 1)/3

f-1(6) = 5/3

3 0

3 years ago

Use the following function rule to find f(2).<br> f(x) = 4 + x<br> f(2)=

lesantik [10]

I’m assuming you just substitute 2 in the equation for x:
4 + x = 4 + 2 = 6

Answer = 6

6 0

1 year ago

Read 2 more answers

The cost of 5 litres of petrol is 260 find the cost of 1 liter and 15 litres of petro?

patriot [66]

Answer:

I got 789

Step-by-step explanation:

260x3 I'm not sure tho

4 0

3 years ago

4. A small high school holds its graduation ceremony in the gym. Because of seating constraints, students are limited to a maxim

Ad libitum [116K]

Answer:

(a) The mean and standard deviation of <em>X</em> is 2.6 and 1.2 respectively.

(b) The mean and standard deviation of <em>T</em> are 390 and 180 respectively.

(c) The distribution of <em>T</em> is <em>N</em> (390, 180²). The probability that all students’ requests can be accommodated is 0.7291.

Step-by-step explanation:

(a)

The random variable <em>X</em> is defined as the number of tickets requested by a randomly selected graduating student.

The probability distribution of the number of tickets wanted by the students for the graduation ceremony is as follows:

X P (X)

0 0.05

1 0.15

2 0.25

3 0.25

4 0.30

The formula to compute the mean is:

$\mu=\sum x\cdot P(X)$

Compute the mean number of tickets requested by a student as follows:

$\mu=\sum x\cdot P(X)\\=(0\times 0.05)+(1\times 0.15)+(2\times 0.25)+(3\times 0.25)+(4\times 0.30)\\=2.6$

The formula of standard deviation of the number of tickets requested by a student as follows:

$\sigma=\sqrt{E(X^{2})-\mu^{2}}$

Compute the standard deviation as follows:

$\sigma=\sqrt{E(X^{2})-\mu^{2}}\\=\sqrt{[(0^{2}\times 0.05)+(1^{2}\times 0.15)+(2^{2}\times 0.25)+(3^{2}\times 0.25)+(4^{2}\times 0.30)]-(2.6)^{2}}\\=\sqrt{1.44}\\=1.2$

Thus, the mean and standard deviation of <em>X</em> is 2.6 and 1.2 respectively.

(b)

The random variable <em>T</em> is defined as the total number of tickets requested by the 150 students graduating this year.

That is, <em>T</em> = 150 <em>X</em>

Compute the mean of <em>T</em> as follows:

$\mu=E(T)\\=E(150\cdot X)\\=150\times E(X)\\=150\times 2.6\\=390$

Compute the standard deviation of <em>T</em> as follows:

$\sigma=SD(T)\\=SD(150\cdot X)\\=\sqrt{V(150\cdot X)}\\=\sqrt{150^{2}}\times SD(X)\\=150\times 1.2\\=180$

Thus, the mean and standard deviation of <em>T</em> are 390 and 180 respectively.

(c)

The maximum number of seats at the gym is, 500.

According to the Central Limit Theorem if we have a population with mean μ and standard deviation σ and we take appropriately huge random samples (n ≥ 30) from the population with replacement, then the distribution of the sum of values of X, i.e ∑X, will be approximately normally distributed.

Here <em>T</em> = total number of seats requested.

Then, the mean of the distribution of the sum of values of X is given by,

$\mu_{T}=n\times \mu_{X}=390$

And the standard deviation of the distribution of the sum of values of X is given by,

$\sigma_{T}=n\times \sigma_{X}=180$

So, the distribution of <em>T</em> is N (390, 180²).

Compute the probability that all students’ requests can be accommodated, i.e. less than 500 seats were requested as follows:

$P(T$

Thus, the probability that all students’ requests can be accommodated is 0.7291.

8 0

3 years ago

The price of an item yesterday was $160 . Today, the price rose to $232 . Find the percentage increase.

mojhsa [17]

Answer:

i guess the answer is $132

5 0

3 years ago

Read 2 more answers