as you see you got this problem wrong becuase Its c :)
btw i got same question are we on same schools lol
Answer:
Option b oxaloacetate is the right one.
Explanation:
There are major eight steps in TCA cycle. Oxaloacetate plays a pivotal role in <u>first and eight step</u>s of cycle.
Step 1. In the first step of the citric acid cycle, acetyl CoA joins with a four-carbon molecule, oxaloacetate, releasing the CoA group and forming a six-carbon molecule called citrate.
Step 8. In the last step of the citric acid cycle, oxaloacetate—the starting four-carbon compound-is regenerated by oxidation of malate. Another molecule of NAD+ is reduced to NADH in the process.
The molecule shown below is a molecule that is generally termed as the energy currency molecule of the cell, and that is ATP.
The components of it include:
1. Adenine nitrogenous base, the far left
2.Ribose, sugar the same sugar found in RNA molecules, middle.
3. Triphosphate - 3 covalently bound phosphate groups ready to split apart as they don't typically like being bonded in that manner, due to charges on phosphate, being negatively charged.
<span>And of a large group of organized compounds occurring in foods and living tissues. </span>
Answer:
D
Explanation:
This is because one of its orbital shells is not filled – the one with 1 electron. This atom will, therefore, want to lose this electron – it takes less energy to do this than gain 7 electrons -- to achieve stable electron configuration. This makes this atom very reactive in a chemical reaction. Usually orbital shells of atoms begin with an S orbital shell that is filled with 2 electrons then P (x,y,z) orbital shells filled with 6 electrons total. There are also higher energy f and d orbitals that each take a maximum 10 and 14 electrons respectively. An atom is stable if its orbitals are fully filled.
