The artistic crop isn't helpful; it cuts off some vertex names.
The circumcenter H is the meet of the perpendicular bisectors of the sides, helpfully drawn. We have right triangle ELH, right angle L, so
EH² = HL² + EL²
EL = √(EH² - HL²) = √(5.06²-2.74²) ≈ 4.2539393507665339
Since HL is a perpendicular bisector of EF, we get congruent segments FL=EL.
Answer: 4.25
Answer:
I think so yeah. not sure though
4(x-y)^4
4((-2)-(-4))^4
4((-2)+4)^4
4(2)^4
4(256)
THE ANSWER IS 512
I think it might be pairs 2 & 3
Answer:
A
Step-by-step explanation:
Reflection over the x axis means that for points A, B, and C, the sign of the y value would change. Since point A is (1, 1), a reflection over the x axis means that it would become (1, -1). We can do the same for points B and C and therefore the answer is graph A
