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yaroslaw [1]
3 years ago
8

What is the shaded area?

Mathematics
1 answer:
Pavlova-9 [17]3 years ago
5 0

Answer:

Step-by-step explanation:

a . possible

b. ehhh

c. possible

d. possible

choose one

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Order the fractions from least to greatest.
pantera1 [17]

Answer:

that would be c

Step-by-step explanation:

is because it is least to greatest I hope this helps you

6 0
2 years ago
Seven times a number is less than or equal to a quantity that is 24 less than that same
Ad libitum [116K]

Answer:

7x\leq x-24

Here, x denotes the required number.

Step-by-step explanation:

Let x denotes the required number that satisfies the following condition.

''seven times a number is less than or equal to a quantity that is 24 less than that same  number''

Seven times a number is equal to 7x

Quantity that is 24 less than that same  number is equal to x-24

Now find the inequality.

As seven times a number is less than or equal to a quantity that is 24 less than that same  number,

7x\leq x-24

6 0
3 years ago
A consulting firm had predicted that 35% of the employees at a large firm would take advantage of a new company Credit Union, bu
m_a_m_a [10]

Answer:

a) 0.4770

b) 3.9945

c) z-statistics seem a large value

Step-by-step explanation:

<u>a. Find the standard deviation of the sample proportion based on the null hypothesis</u>

Based on the null hypothesis:

p_{0}: 0.35

and the standard deviation σ = \sqrt{p_{0} *(1-p_{0}) } =\sqrt{0.35 *0.65 } ≈0.4770

<u>b. Find the z statistic</u>

z-statistic is calculated as follows:

z=\frac{X-p_{o} }{\frac{s}{\sqrt{N} } } where

  • X is the proportion of employees in the survey who take advantage of the Credit Union (\frac{138}{300}=0.46)
  • p_{0} is the proportion in null hypothesis (0.35)
  • s is the standard deviation (0.4770)
  • N is the sample size (300)

putting the numbers in the formula:

z=\frac{0.46-0.35} }{\frac{0.4770}{\sqrt{300} } } = 3.9945

<u>c. Does the z statistic seem like a particularly large or small value?</u>

z-statistics seem a large value, which will cause us to reject the null hypothesis.

4 0
3 years ago
If X=2<br><br> X3+X (that 3 is supposed to be representing that the X is cubed)
seropon [69]
X^3+x and x=2
=(2)^3+2
=8+2
=10
7 0
3 years ago
If cos theta= -8/17 and theta is in quadrant 3, what is cos2 theta and tan2 theta
Karo-lina-s [1.5K]
\bf cos(\theta)=\cfrac{adjacent}{hypotenuse}\qquad  &#10;\begin{array}{llll}&#10;\textit{now, hypotenuse is always positive}\\&#10;\textit{since it's just the radius}&#10;\end{array}&#10;\\\\\\&#10;thus\qquad cos(\theta)=\cfrac{-8}{17}\cfrac{\leftarrow adjacent=a}{\leftarrow  hypotenuse=c}

since the hypotenuse is just the radius unit, is never negative, so the - in front of 8/17 is likely the numerator's, or the adjacent's side

now, let us use the pythagorean theorem, to find the opposite side, or "b"

\bf c^2=a^2+b^2\implies \pm\sqrt{c^2-a^2}=b\qquad &#10;\begin{cases}&#10;c=hypotenuse\\&#10;a=adjacent\\&#10;b=opposite&#10;\end{cases}&#10;\\\\\\&#10;\pm\sqrt{17^2-(-8)^2}=b\implies \pm\sqrt{225}=b\implies \pm 15=b

so... which is it then? +15 or -15? since the root gives us both, well
angle θ, we know is on the 3rd quadrant, on the 3rd quadrant, both, the adjacent(x) and the opposite(y) sides are negative, that means,  -15 = b

so, now we know, a = -8, b = -15, and c = 17
let us plug those fellows in the double-angle identities then

\bf \textit{Double Angle Identities}&#10;\\ \quad \\&#10;sin(2\theta)=2sin(\theta)cos(\theta)&#10;\\ \quad \\&#10;cos(2\theta)=&#10;\begin{cases}&#10;cos^2(\theta)-sin^2(\theta)\\&#10;\boxed{1-2sin^2(\theta)}\\&#10;2cos^2(\theta)-1&#10;\end{cases}&#10;\\ \quad \\&#10;tan(2\theta)=\cfrac{2tan(\theta)}{1-tan^2(\theta)}\\\\&#10;-----------------------------\\\\&#10;cos(2\theta)=1-2sin^2(\theta)\implies cos(2\theta)=1-2\left( \cfrac{-15}{17} \right)^2&#10;\\\\\\&#10;cos(2\theta)=1-\cfrac{450}{289}\implies cos(2\theta)=-\cfrac{161}{289}




\bf tan(2\theta)=\cfrac{2tan(\theta)}{1-tan^2(\theta)}\implies tan(2\theta)=\cfrac{2\left( \frac{-15}{-8} \right)}{1-\left( \frac{-15}{-8} \right)^2}&#10;\\\\\\&#10;tan(2\theta)=\cfrac{\frac{15}{4}}{1-\frac{225}{64}}\implies tan(2\theta)=\cfrac{\frac{15}{4}}{-\frac{161}{64}}&#10;\\\\\\&#10;tan(2\theta)=\cfrac{15}{4}\cdot \cfrac{-64}{161}\implies tan(2\theta)=-\cfrac{240}{161}
6 0
3 years ago
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