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qwelly [4]
2 years ago
7

Name a number that is not a whole number, a number that is not an integer, a number that is not a rational number, and a number

that is not an irrational number. Do not use the same number twice.​
Mathematics
1 answer:
Pani-rosa [81]2 years ago
4 0

Answer:

10, 5, .75, π

Step-by-step explanation:

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A married couple had a combined annual income of 63,000. The wife made 7,000 more than her husband. What was each of their incom
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The wife made 33,500 and the husband made 29,500
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50 POINTS!!!
san4es73 [151]

Step-by-step explanation:

<u>Step 1:  Determine an ordered pair</u>

A solution of an equation just means that the point lies on the line.  We can find any y-value when we plug in a specific x-value.  For example, if we want to know what ordered pair lies at x=1, we just plug in y = -1/2(1) and solve for y which gives us -1/2.  This gives us an ordered pair of (1, -1/2).  We can continue to do this for any x value.

We can also reverse the order and plug in the y-value and get the x-value in order to accomplish the same goal but it's a bit harder.

Hope this helps!

6 0
1 year ago
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What is the value of tan(60°)? One-half StartRoot 3 EndRoot StartFraction StartRoot 3 EndRoot Over 2 EndFraction StartFraction 1
Ratling [72]

Answer:

\sqrt3

Step-by-step explanation:

To find:

The value of tan60^\circ = ?

Solution:

Kindly consider the equilateral \triangle ABC as attached in the answer area.

Let the side of triangle = a units

Let us draw the perpendicular from vertex A to side BC.

It will divide the side BC in two equal parts.

i.e. BD = DC = \frac{a}{2}

Using Pythagorean Theorem in \triangle ABD:

\text{Hypotenuse}^{2} = \text{Base}^{2} + \text{Perpendicular}^{2}

Side AD = \frac{\sqrt3}{2}a

Using Trigonometric ratio:

tan\theta = \dfrac{Perpendicular}{Base}

tanB = \dfrac{AD}{BD}

Putting the values of AD and BD:

tan60^\circ=\dfrac{\frac{\sqrt3}{2}a}{\frac{1}{2}a}\\\Rightarrow tan60^\circ = \bold{\sqrt3}

5 0
2 years ago
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Answer ,how to do it.
guapka [62]

Answer:

<u>The system has two solutions:</u>

<u>x₁ = 5  ⇒ y₁ = -10</u>

<u>x₂ = -2 ⇒ y₂ = 11</u>

Step-by-step explanation:

Let's solve the system of equations, this way:

y = -3x + 5

y = x ² - 6x - 5

Replacing y in the 2nd equation:

y = x ² - 6x - 5

-3x + 5 = x ² - 6x - 5

x ² - 3x - 10 = 0

Solving for x, using the quadratic formula:

(3 +/- √(9 -4 * 1 * -10))/2 * 1

(3 +/- √9 + 40)/2

(3 +/- √49)/2

(3 +/- 7)/2

x₁ = 10/2 = 5

x₂ = -4/2 = -2

x₁ = 5  ⇒ y₁ = -10

x₂ = -2 ⇒ y₂ = 11

<u>As we can see the system has two different solutions</u>

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3 years ago
An inequality is shown below.
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B.
You are looking for something that does not let 25x go over 80.
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