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murzikaleks [220]
3 years ago
15

The cost c in $ of producing x items is in the equation c=x/7+1 which of the following choices will find the cost c if x is 35

Mathematics
1 answer:
riadik2000 [5.3K]3 years ago
3 0

Answer:

care of it and I will get back to you with a new one for me and support you in whatever way

Step-by-step explanation:

try to get the morning and then we can go from there to the meeting tonight but I can tomorrow

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Step-by-step explanation:

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5 0
4 years ago
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Any clues on this please help
AysviL [449]
Im pretty sure points K and F
4 0
3 years ago
Use logarithmic differentiation to find dy/dx: y=((x^3)(2x+3)^1/2) / (x-2)^2
sukhopar [10]
y=\frac { { { x }^{ 3 }\left( 2x+3 \right)  }^{ \frac { 1 }{ 2 }  } }{ { \left( x-2 \right)  }^{ 2 } }

\\ \\ { \left( x-2 \right)  }^{ 2 }\cdot y={ x }^{ 3 }{ \left( 2x+3 \right)  }^{ \frac { 1 }{ 2 }  }

\\ \\ \ln { \left( { \left( x-2 \right)  }^{ 2 }\cdot y \right)  } =\ln { \left( { x }^{ 3 }{ \left( 2x+3 \right)  }^{ \frac { 1 }{ 2 }  } \right)  }

\\ \\ \ln { \left( { \left( x-2 \right)  }^{ 2 } \right)  } +\ln { y } =\ln { \left( { x }^{ 3 } \right)  } +\ln { \left( { \left( 2x+3 \right)  }^{ \frac { 1 }{ 2 }  } \right)  }

\\ \\ 2\ln { \left( x-2 \right)  } +\ln { y } =3\ln { x } +\frac { 1 }{ 2 } \ln { \left( 2x+3 \right)  }

\\ \\ \ln { y } =3\ln { x } -2\ln { \left( x-2 \right)  } +\frac { 1 }{ 2 } \ln { \left( 2x+3 \right)  }

\\ \\ \frac { 1 }{ y } \cdot \frac { dy }{ dx } =\frac { 3 }{ x } -\frac { 2 }{ x-2 } +\frac { 1 }{ 2x+3 }

\\ \\ y\cdot \frac { 1 }{ y } \cdot \frac { dy }{ dx } =y\left( \frac { 3 }{ x } -\frac { 2 }{ x-2 } +\frac { 1 }{ 2x+3 }  \right)

\\ \\ \frac { dy }{ dx } =\frac { { x }^{ 3 }\sqrt { 2x+3 }  }{ { \left( x-2 \right)  }^{ 2 } } \cdot \left( \frac { 3 }{ x } -\frac { 2 }{ x-2 } +\frac { 1 }{ 2x+3 }  \right)
4 0
3 years ago
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