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3 years ago

The cost c in $ of producing x items is in the equation c=x/7+1 which of the following choices will find the cost c if x is 35

Mathematics

1 answer:

riadik2000 [5.3K]3 years ago

3 0

Answer:

care of it and I will get back to you with a new one for me and support you in whatever way

Step-by-step explanation:

try to get the morning and then we can go from there to the meeting tonight but I can tomorrow

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Janelle has 75$. She buys jeans that are on sale for half the price and then uses an In store coupon for 10$ off. After paying $

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4 years ago

6x-3y =15<br><br><br> (System of Equations)

Vadim26 [7]

Answer:

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Step-by-step explanation:

So yeah... that's the answer

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3 years ago

Which expression represents "3 more than twice a number"? Choices: 2n−3 3−2n 2n+3 2+n+3

Alekssandra [29.7K]

2n+3

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5 0

4 years ago

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Any clues on this please help

AysviL [449]

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3 years ago

Use logarithmic differentiation to find dy/dx: y=((x^3)(2x+3)^1/2) / (x-2)^2

sukhopar [10]

$y=\frac { { { x }^{ 3 }\left( 2x+3 \right) }^{ \frac { 1 }{ 2 } } }{ { \left( x-2 \right) }^{ 2 } }$

$\\ \\ { \left( x-2 \right) }^{ 2 }\cdot y={ x }^{ 3 }{ \left( 2x+3 \right) }^{ \frac { 1 }{ 2 } }$

$\\ \\ \ln { \left( { \left( x-2 \right) }^{ 2 }\cdot y \right) } =\ln { \left( { x }^{ 3 }{ \left( 2x+3 \right) }^{ \frac { 1 }{ 2 } } \right) }$

$\\ \\ \ln { \left( { \left( x-2 \right) }^{ 2 } \right) } +\ln { y } =\ln { \left( { x }^{ 3 } \right) } +\ln { \left( { \left( 2x+3 \right) }^{ \frac { 1 }{ 2 } } \right) }$

$\\ \\ 2\ln { \left( x-2 \right) } +\ln { y } =3\ln { x } +\frac { 1 }{ 2 } \ln { \left( 2x+3 \right) }$

$\\ \\ \ln { y } =3\ln { x } -2\ln { \left( x-2 \right) } +\frac { 1 }{ 2 } \ln { \left( 2x+3 \right) }$

$\\ \\ \frac { 1 }{ y } \cdot \frac { dy }{ dx } =\frac { 3 }{ x } -\frac { 2 }{ x-2 } +\frac { 1 }{ 2x+3 }$

$\\ \\ y\cdot \frac { 1 }{ y } \cdot \frac { dy }{ dx } =y\left( \frac { 3 }{ x } -\frac { 2 }{ x-2 } +\frac { 1 }{ 2x+3 } \right)$

$\\ \\ \frac { dy }{ dx } =\frac { { x }^{ 3 }\sqrt { 2x+3 } }{ { \left( x-2 \right) }^{ 2 } } \cdot \left( \frac { 3 }{ x } -\frac { 2 }{ x-2 } +\frac { 1 }{ 2x+3 } \right)$

4 0

3 years ago

Read 2 more answers