Answer:
quantity a is halfed
Corrected question;
A quantity a varies inversely as a quantity b, if, when b changes a changes in the inverse ratio. What happens to the quantity a if the quantity b doubles?
Step-by-step explanation:
Analysing the question;
A quantity a varies inversely as a quantity b,
a ∝ 1/b
a = k/b ......1
when b changes a changes in the inverse ratio;
Since the change at the same ratio but inversely, k = 1
So, equation 1 becomes;
a = 1/b
If the quantity b doubles,
ab = 1
a1b1 = a2b2
When b doubles, b2 = 2b1
a1b1 = a2(2b1)
Making a2 the subject of formula;
a2 = a1b1/(2b1)
a2 = a1/2
Therefore, when b doubles, a will be divided by 2, that means a is halfed.
a. Parameterize 
by
with 
.
b/c. The line integral of 
over is
d. Notice that we can write the line integral as
By Green's theorem, the line integral is equivalent to
where 
is the triangle bounded by , and this integral is simply twice the area of . is a right triangle with legs 2 and 5, so its area is 5 and the integral's value is 10.
The answer is 6.5t2+0.5t−5.5 , it’s simplified
