The x intercept occurs when y = 0.
0=(x+2)^2 - 1
1=(x+2)^2
Take the square root of both sides. Note that the sqrt of 1 is 1. Then solve for x.
1=x+2
-1=x
The x intercept is -1.
The y intercept occurs when x=0.
y=(0+2)^2 - 1
y=2^2 -1
y=4-1
y=3
The y intercept is 3.
Now, to find the vertex...
This parabola is currently in a format called the vertex form, which is:
f(x) = (x-h)^2 + k
where (h, k) is the vertex.
Therefore, the vertex is (-2, -1).
Use the Product Rule: x^ax^b = x^a + b
6x^3 + 1y^2 + 6
Simplify 3 + 1 to 4
6x^4y^2 + 6
Simplify 2 + 6 to 8
<u>= C) 6x^4 y^8</u>
AB and AC ................................
