Answer:
Step-by-step explanation:
The product of distances to the circle along a secant is the same for all secants intersecting a given point.
a. Secants SW and QT intersect at U. Thus ...
(UT)(UQ) = (US)(UW)
(1.5)(4) = (SU)(3)
SU = (4)(1.5)/3
SU = 2
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b. Secants PT and PX intersect at P. Thus ...
(PQ)(PT) = (PR)(PX)
PX = (PQ)(PT)/PR) = (2.5)(2.5 +4 +1.5)/3 = 20/3
PX = 6 2/3
∆x = (4--4)=8
∆y = (7--3)= 10
Step-by-step explanation:
distance is given by;
d² = (∆y)²+ (∆x)²
d = √((∆y)²+ (∆x)²)
d = √((4+4)² + (7+3)²)
d = √((8²) + (10²))
d = √(64+100)
d = √164
<em><u>d =12.806 units</u></em>
Answer:
2
Step-by-step explanation:
Subtract 1 from 7, and then divide 6 by 3.
283
Start by doing multiplication and division from left to right to follow the order of operations.
270 + 12 / 3 + 9
270 + 4 + 9
Now do addition and subtraction from left to right.
274 + 9
283
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Answer:
the first one
Step-by-step explanation:
