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Alika [10]
3 years ago
5

Use the distance formula and the Pythagorean theorem to find the distance,to the nearest tenth,between each pair of points

Mathematics
1 answer:
MrMuchimi3 years ago
4 0
I think you should use the formula
You might be interested in
How to simplify 20/10
Andreyy89

In order to get the answer to this question you will have to find the common factor and then divide the numerator and denominator by the common factor to get the answer.

\frac{20}{10}

CF=10

20\div10=2

10\div10=1

\frac{2}{1} =2

= \frac{2}{1} or2

Therefore the answer is "2."

Hope this helps.

4 0
3 years ago
Solve for m 1/C+1/m=1/z
9966 [12]
Answer:  " m = zC / (C − z) " .
___________________________________
Explanation:
_________________________
Given:  1/C + 1/m = 1/z ;  Solve for "m".

Subtract  "1/C" from each side of the equation:
____________________________________
1/C + 1/m − 1/C = 1/z − 1/C  ;

to get:  1/m = 1/z − 1/C ;
____________________________________
Now, multiply the ENTIRE EQUATION (both sides); by "(mzC"); to get ride of the fractions:
_________________

mzC {1/m = 1/z − 1/C} ;

to get:  zC = mC − mz ;

Factor out an "m" on the "right-hand side" of the equation:

zC = m(C − z) ;  Divide EACH side of the equation by "(C − z)" ; to isolate "m" on one side of the equation;

zC / (C − z) = m(C − z) / m ;  to get:   24/8 = 3  24

zC/ (C − z) = m ;   ↔   m = zC/ (C − z) .
___________________________________________________
4 0
3 years ago
278675536638382+23747293468798009 =
Ilia_Sergeevich [38]

Answer:

2.40259690054e+16

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Find an equation of the circle that has center (6, 2) and passes through (-2,-6).
Irina18 [472]

Answer:

(x - 6)² + (y - 2)² = 128

Step-by-step explanation:

Given as the circle has center ( 6 , 2)

and it passes through points (-2 , -6)

Now , standard equation of circle is (x -a)² + (y- b)² = r²   , where (a , b) is center and r is the radius .

Again from given center the circle equation is

(x- 6)² + (y- 2)² = r²

Now this circle passes through points (-2 , -6)

so, (-2 -6)² + (-6 -2)²  = r²

so, 8²  + 8² = r²

Or, 128  = r²

i.e Radius pf this circle = 8\sqrt{2}

Hence the circle equation formed is

(x- 6)² +( y-2)² = 128   Answer

6 0
3 years ago
Need help with 6th grade math plz help thanks
tankabanditka [31]

Answer:

D.

Step-by-step explanation:

the graph,, top of the graph says year and students enrolled

4 0
3 years ago
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