All categories

3 years ago

PLEASE HELP ME WITH THIS

Mathematics

2 answers:

Leviafan [203]3 years ago

8 0

Answer:

arithmetic

Step-by-step explanation:

Dmitry_Shevchenko [17]3 years ago

6 0

Answer:

that would be Arithmetic

Step-by-step explanation:

You might be interested in

The number of students enrolled at a college is 17,000 and grows 6% each year.

Ad libitum [116K]

Answer:

1020 new students per year.

Step-by-step explanation:

5 0

3 years ago

Write a situation in which positive and negative numbers are used to describe values that have opposite meaning. What does 0 rep

mote1985 [20]

This would be something like [5] or -[-5] which is absolute value (>.<)

8 0

3 years ago

I need help on this Pls

lina2011 [118]

Answer:

y = 6x + 9 :))))))))))((

6 0

2 years ago

Read 2 more answers

Help with this immediately

ratelena [41]

Answer:

just type the values in your google

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Find values of  that satisfy the equation for 0º    360º and 0  θ  2 . Give answers in degrees and radians.

suter [353]

Answer:

$\theta = 30^\circ, 330^\circ$

$\theta = \frac{\pi}{6}, \frac{11\pi}{6}$

Step-by-step explanation:

Given [Missing from the question]

Equation:

$cos\theta = \frac{\sqrt 3}{2}$

Interval:

$0 \le \theta \le 360$

$0 \le \theta \le 2\pi$

Required

Determine the values of $\theta$

The given expression:

$cos\theta = \frac{\sqrt 3}{2}$

... shows that the value of $\theta$ is positive

The cosine of an angle has positive values in the first and the fourth quadrants.

So, we have:

$cos\theta = \frac{\sqrt 3}{2}$

Take arccos of both sides

$\theta = cos^{-1}(\frac{\sqrt 3}{2})$

$\theta = 30$ --- In the first quadrant

In the fourth quadrant, the value is:

$\theta = 360 -30$

$\theta = 330$

So, the values of $\theta$ in degrees are:

$\theta = 30^\circ, 330^\circ$

Convert to radians (Multiply both angles by $\pi/180$ )

So, we have:

$\theta = \frac{30 * \pi}{180}, \frac{330 * \pi}{180}$

$\theta = \frac{\pi}{6}, \frac{33 * \pi}{18}$

$\theta = \frac{\pi}{6}, \frac{11 * \pi}{6}$

$\theta = \frac{\pi}{6}, \frac{11\pi}{6}$

8 0

2 years ago