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SSSSS [86.1K]
3 years ago
11

what's the equation in point slope form of the line that passes through the point (3, 1) and has a slope of -2

Mathematics
2 answers:
yarga [219]3 years ago
7 0

Answer:

The equation of the required line is,

<em>y</em> = -2<em>x</em> + 7

Step-by-step explanation:

We know that equation of a line passing through the point (<em>x</em>₁, <em>y</em>₁) and having slope 'm' is given by

(<em>y</em> - <em>y</em>₁) = m(<em>x</em> - <em>x</em>₁)

Now, the required line passes through the point (3, 1) and has a slope of -2.

So, (<em>x</em>₁, <em>y</em>₁) = (3, 1) and m = -2

So, equation of the line passing through (3, 1) and having a slope of -2 is given by,

  <em>y</em> - 1 = -2(<em>x</em> - 3)

⇒<em>y</em> - 1 = -2<em>x</em> + 6

⇒<em>y</em> = -2<em>x</em> + 6 + 1

⇒<em>y</em> = -2<em>x</em> + 7

So, the required equation of line in point-slope form is,

<em>y</em> = -2<em>x</em> + 7

Savatey [412]3 years ago
3 0

Answer:

equation: y = -2x + 7

Step-by-step explanation:

y = mx + b   M: slope     b: y intercept

m = -2

x = 3 and y = 1

b = y - mx = 1 - (- 2) x 3 = 7

equation: y = -2x + 7

check:     ( 3,1)     -2 x 3 + 7 = 1

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