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3 years ago

I need help on this question

Mathematics

2 answers:

miss Akunina [59]3 years ago

6 0

Answer:

The result for Tan C, is 24 / 7

Step-by-step explanation:

-Three things to remember:

$sin = \frac{opposite}{hypotenuse}$

$cos = \frac{adjacent}{hypotenuse}$

$tan = \frac{opposite}{adjacent}$

- If you are looking for tan C, then you need to look for $\frac{opposite}{adjacent}$ from the triangle.

-So, for the $opposite$ of the triangle would be 48 and the $adjacent$ would be 14:

$tan$ $C$ $=\frac{48}{14}$

-Then, solve for it and you will get $\frac{24}{7}$ :

$tan$ $C$ $=\frac{48}{14} = \frac{24}{7}$

So, therefore, the result for tan C is 24 / 7.

Alinara [238K]3 years ago

3 0

Answer:

Step-by-step explanation:

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nasty-shy [4]

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3 years ago

Solve the equation for all real values of x.<br> cosxtanx - 2 cos x=-1

IceJOKER [234]

Solution to equation $cosxtanx - 2 cos^2 x=-1$ for all real values of x is $x=2k\pi + \frac{\pi}{6} , x=2k\pi + \frac{5\pi}{6}$ .

<u>Step-by-step explanation:</u>

Here we have , $cosxtanx - 2 cos^2 x=-1$ . Let's solve :

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⇒ $cosx(\frac{sinx}{cosx}) - 2 cos^2 x=-1$

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⇒ $sinx = 2 (1-sin^2x)-1$

⇒ $sinx = 1-2sin^2x$

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By quadratic formula :

⇒ $sinx = \frac{-b \pm \sqrt{b^2-4ac} }{2a}$

⇒ $sinx = \frac{-1 \pm \sqrt{1^2-4(2)(-1)} }{2(2)}$

⇒ $sinx = \frac{-1 \pm3}{4}$

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⇒ $sinx = sin\frac{\pi}{6} , sinx = sin\frac{3\pi}{2}$

⇒ $x=\frac{\pi}{6} , x=\frac{3\pi}{2}$

But at $x=\frac{3\pi}{2}$ we have equation undefined as $cos\frac{3\pi}{2}=0$ . Hence only solution is :

⇒ $x=\frac{\pi}{6}$

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Now , General Solution is given by :

⇒ $x=2k\pi + \frac{\pi}{6} , x=2k\pi + \frac{5\pi}{6}$

Therefore , Solution to equation $cosxtanx - 2 cos^2 x=-1$ for all real values of x is $x=2k\pi + \frac{\pi}{6} , x=2k\pi + \frac{5\pi}{6}$ .

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3 years ago

A $7,600 par value bond sells for $7,373 . The coupon rate is 5.30% . What is the current yield

marta [7]

Answer:

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Step-by-step explanation:

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bearhunter [10]

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garik1379 [7]

Answer:

Step-by-step explanation:

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3 years ago

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