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worty [1.4K]
3 years ago
7

What is the answer 6²÷2(3)+4=

Mathematics
2 answers:
Annette [7]3 years ago
7 0
6²÷2(3)+4

Use the order of operations:
GEMDAS (grouping, exponents, multiplication/division, addition/subtraction)

First is grouping.
While there is a number inside parentheses, there aren't any operations in there we have to do first. The 2(3) is just another way to write multiplication. (2×3)

Second is exponents.
We do have an exponent here, 6².
The ² means to multiply something by itself. 6² = 6×6 = 36

Now our expression is 36÷2(3)+4

Next is multiplication/division. We can do these in any order. (either do the ×3 first or the ÷2 first, it doesn't matter)
Let's start at the left with 36÷2, which equals 18. (check: 18×2=36)
Now, we'll do the 18×3 = 54
If we were to do 36(3)÷2 that would work too-- 36×3÷2 = 108÷2 = 54.
Now while you can do these in any order, what you can <em>not</em> do is multiply the dividend 2 by 3. That would give 36÷6 = 6, which is incorrect. It's not something you need to fret over, just go from left to right doing your multiplication/division and you shouldn't ever have this problem.

Now we have 54 + 4 which is clearly 58.
madreJ [45]3 years ago
3 0

The answer 6²÷2(3)+4 is 10 (PEMDAS rule) and 58 (many computer language)

<h3>Further explanation </h3>

Mathematical expression is a symbols of finite combination that is well-formed according to rules that depend on the context.

There are two correct answers for this question

6^2:2(3)+4\\6^2:6+4\\6+4\\=10 according to the PEMDAS rule.

"PEMDAS." means: Parentheses, Exponents, Multiplication, Division, Addition, and Subtraction. PEMDAS is often expanded to the mnemonic "Please Excuse My Dear Aunt Sally". In mathematics and computer programming, the order of operations is a rules collectionthat reflect conventions that procedure to perform first in order to evaluate a given mathematical expression. Addition and multiplication are operations at a "different level" from each other, where the multiplication is repeated addition so it makes sense to treat them differently. On the other hand, subtraction is a special version of addition and is treated the same.

or

6^2:2(3)+4\\18(3)+4\\54+4\\=58 according to many computer language. A programming language is a tool for humans to express ideas to computers. While the developers have many things in common, there is natural variety in the way that their minds work.

<h3>Learn more</h3>
  1. Learn more about  math problem brainly.com/question/558496
  2. Learn more about expressions brainly.com/question/9657981
  3. Learn more about  the exponential operation brainly.com/question/1564163

<h3>Answer details</h3>

Grade:  9

Subject:  Mathematics

Chapter:  expressions

Keywords: math problem, expressions,  the exponential operation, parentheses, multiplication  

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Answer:

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Step-by-step explanation:

Given the expression:

\dfrac{4+\sqrt{16-(4)(5)}}{2}

To find:

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First of all, learn the concept of i (pronounced as <em>iota</em>) which is used to represent the complex numbers. Especially the imaginary part of the complex number is represented by i.

Value of i =\sqrt{-1}.

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\dfrac{4+\sqrt{16-(4)(5)}}{2}\\\Rightarrow \dfrac{4+\sqrt{16-(4\times 5)}}{2}\\\Rightarrow \dfrac{4+\sqrt{16-20}}{2}\\\Rightarrow \dfrac{4+\sqrt{-4}}{2}\\\Rightarrow \dfrac{4+\sqrt{(-1)(4)}}{2}\\\Rightarrow \dfrac{4+\sqrt{(-1)}\sqrt4}{2}\\\Rightarrow \dfrac{4+\sqrt4i}{2} \ \ \ \ \ (\because \sqrt{-1} =i) \\\Rightarrow \dfrac{4+2i}{2}\\\Rightarrow 2+i

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Let us compare with standard form a+bi so we get a =2, b =1.

\therefore The standard form of

\dfrac{4+\sqrt{16-(4)(5)}}{2}

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