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3 years ago

There are approximately 1 1/2 kilometers in one mile. Approximately how many kilometers are in 6 miles?

Mathematics

1 answer:

adelina 88 [10]3 years ago

6 0

1.5 times 6 is equal to 9. So the answer is 9 kilometers

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The quantity y varies directly with the square of x and inversely with z. When x is 9 and z is 27, y is 6. What is the constant

ira [324]

$\bf \qquad \qquad \textit{double proportional variation}
\\\\
\begin{array}{llll}
\textit{\underline{y} varies directly with \underline{x}}\\
\textit{and inversely with \underline{z}}
\end{array}\implies y=\cfrac{kx}{z}\impliedby 
\begin{array}{llll}
k=constant\ of\\
\qquad variation
\end{array}\\\\
-------------------------------$

$\bf \stackrel{\textit{\underline{y} varies directly with the square of \underline{x} and inversely with \underline{z}}}{y=\cfrac{kx^2}{z}}
\\\\\\
\textit{we also know that }
\begin{cases}
x=9\\
z=27\\
y=6
\end{cases}\implies 6=\cfrac{k9^2}{27}
\\\\\\
\cfrac{27\cdot 6}{9^2}=k\implies 2=k$

4 0

3 years ago

The function for the cost of materials to make a muffin is f(x)=3/4x+3, where x is the number of muffins. The function for the s

scoray [572]

the first one is from walmart which is 5.99$ the other store sells it for 3.49 which one is better to buy

8 0

3 years ago

Plsss help ASAP This is the question

krok68 [10]

Answer: 81

since it's the 4th power then you do 3x3x3x3= 81

Step-by-step explanation:

5 0

3 years ago

The net worthw(t) of a company is growing at a rate of′(t) = 2000−121t2dollarsper year, wheretis in years since 1990.(a) If the

stiv31 [10]

Answer:

The worth of the company in 2000 is $56,000.

Step-by-step explanation:

The growth rate of the company is:

$f'(t)=2000-12t^{2}$

To determine the worth of the company in 2000, first compute the change in the net worth during the period 1990 (t = 0) to 2000 (t = 10) as follows:

$\int\limits^{10}_{0} {2000-12t^{2}} \, dt =\int\limits^{10}_{0} {2000} \, dt-12\int\limits^{10}_{0} {t^{2}} \, dt=2000 |t|^{10}_{0}-12|\frac{t^{3}}{3}|^{10}_{0}\\=(2000\times10)-(4\times10^{3})\\=20000-4000\\=16000$

The increase in the company's net worth from 1990 to 2000 is $16,000.

If the company's worth was $40,000 in 1990 then the worth of the company in 2000 is:

Worth in 2000 = Worth in 1990 + Net increase in company's worth

$=40000+16000\\=56000$

Thus, the worth of the company in 2000 is $56,000.

4 0

3 years ago

I will give brainliest to first CORRECT answer.

astraxan [27]

Answer:

C. 576 ft.

Step-by-step explanation:

If the garden has a perimeter of 72feet and the lengths of each of the sides are lengthened by a factor of 8.

Perimeter of the enlarged garden = perimeter before enlargement x enlargement factor

That’s 72 x 8

576feet

7 0

3 years ago

Read 2 more answers

There are approximately 1 1/2 kilometers in one mile. Approximately how many kilometers are in 6 miles​?

There are approximately 1 1/2 kilometers in one mile. Approximately how many kilometers are in 6 miles?