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3241004551 [841]
2 years ago
8

Leslie took a total of 40 quizzes over the course of 5 weeks. After attending 7 weeks of school this quarter, how many quizzes w

ill Leslie have taken in total? Solve using unit rates.
Mathematics
1 answer:
kow [346]2 years ago
5 0

Answer:

56 quizzes

Step-by-step explanation:

40 quizzes = 5 weeks

To find the unit rate of quizzes / week, we can divide both sides by 5

40/5 quizzes = 5/5 weeks

8 quizzes = 1 week

Multiply both sides by 7 to find the amount of quizzes in 7 weeks

8 * 7 quizzes = 1 * 7 weeks

56 quizzes = 7 weeks

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Find the area of the sector.<br> 1350<br> 18 km
harina [27]

Answer:

21870 km^2

Step-by-step explanation:

Area of sector=1/2r^2(theta)

Where r=18 km and theta=135

Area of sector=1/2(18)^2(135)

=1/2(324)(135)

=1/2(43740)

=21870 km^2

7 0
3 years ago
Read 2 more answers
I need to figure out how many solutions does the system of equations below have.
Aleonysh [2.5K]

Answer:

The system has one solution.

Step-by-step explanation:

To find the number of solutions of the system, we equal both equations for y.

If we have ax = b, in which both a and b are different of 0, we have one solution.

If both a and b are 0, we have infinite solutions.

If a is 0 and b is not, there are no solutions.

y=6/7x-8 and y=7/9x+10/9

So

\frac{6x}{7} - 8 = \frac{7x}{9} + \frac{10}{9}

\frac{6x}{7} - \frac{7x}{9} = \frac{10}{9} + 8

\frac{54x - 49x}{63} = \frac{10}{9} + \frac{72}{9}

\frac{5x}{63} = \frac{82}{9}

45x = 63*82

Both a and b are different of 0, so the system has one solution.

6 0
2 years ago
Draw a quadrilateral that has that least 2 right angels
AlexFokin [52]

Answer:

there are 2 right angles

Step-by-step explanation:

8 0
3 years ago
What is 4log1/2^w(2log1/2^u-3log1/2^v written as a single logarithm?
IrinaK [193]
Given:

4log1/2^w (2log1/2^u-3log1/2^v)

Req'd:

Single logarithm = ?

Sol'n:

First remove the parenthesis,

4 log 1/2 (w) + 2 log 1/2 (u) - 3 log 1/2 (v)

Simplify each term,

Simplify the 4 log 1/2 (w) by moving the constant 4 inside the logarithm;
Simplify the 2 log 1/2 (u) by moving the constant 2 inside the logarithm;
Simplify the -3 log 1/2 (v) by moving the constant -3 inside the logarithm:

 log 1/2 (w^4)  + 2 log 1/2 (u) - 3 log 1/2 (v) 
log 1/2 (w^4) + log 1/2 (u^2) - log 1/2 (v^3)

We have to use the product property of logarithms which is log of b (x) + log of b (y) = log of b (xy):

Thus,

Log of 1/2 (w^4 u^2) - log of 1/2 (v^3) 

then use the quotient property of logarithms which is log of b (x)  - log of b (y) = log of b (x/y)

Therefore, 

log of 1/2 (w^4 u^2 / v^3)

and for the final step and answer, reorder or rearrange w^4 and u^2:

log of 1/2 (u^2 w^4 / v^3)  
8 0
3 years ago
Read 2 more answers
In the diagram below, m_MON = 1249, m _ MOP = 2x + 1, and m2 NOP = 2x
miv72 [106K]

Answer:

The answer is below

Step-by-step explanation:

The Angle Addition Postulate states that the measure of an angle formed by two or more angles which are placed side by side is the sum of the measures of the two angles.

Therefore:

∠MON = ∠MOP + ∠NOP (angle addition postulate)

Substituting values gives:

124 = (2x + 1) + (2x + 1)

124 = 2x + 2x + 1 + 1

124 = 4x + 2

subtracting 2 from both sides of the equation:

124 - 2 = 4x + 2 - 2

4x = 122

Dividing through by 4:

4x / 4 = 122 / 4

x = 30.5

Therefore ∠MOP = 2x + 1 = 2(30.5) + 1 = 62°, ∠NOP = 2x + 1 = 2(30.5) + 1 = 62°

∠MOP = 62°, ∠NOP = 62°

5 0
3 years ago
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